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3 years ago

What is the solution set to the inequality (4x-3)(2x-1) greater than or equal to 0?

Mathematics

2 answers:

Anton [14]3 years ago

4 0

Answer:

Step-by-step explanation:

got it on edge

taurus [48]3 years ago

3 0

ANSWER

$x \leqslant \frac{1}{2} \: or \: x \geqslant \frac{3}{4}$

EXPLANATION

The given inequality is:

$(4x - 3)(2x - 1) \geqslant 0$

We solve the corresponding quadratic equation to obtain,

$(4x - 3)(2x - 1) = 0$

This implies that;

$x = \frac{3}{4} \: or \: x = \frac{1}{2}$

We use the number line to solve the inequality as shown in the attachment.

$x \leqslant \frac{1}{2} \: or \: x \geqslant \frac{3}{4}$

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Which table represent a linear function

777dan777 [17]

Answer:

The last answer is correct. (x: 1,2,3,4 ; y: -5,0,5,10)

Step-by-step explanation:

In a linear function, the rate of increase/decrease is constant (the same). For the last answer, since for every x increase, y increases by 5, it is linear and has a constant rate of change.

3 0

3 years ago

Find f(-2) f(x)=9x^2-5x+2

borishaifa [10]

Find f(-2) f(x)=9x^2-5x+2

f(-2) means replace x in the equation with -2:

f(-2)=9(-2)^2-5(-2)+2

= 9(4) +10 + 2

= 36 +10 + 2

= 48

f(-2) = 48

4 0

3 years ago

Iq scores are normally distributed with a mean of 100 and a standard deviation of 15.

bearhunter [10]

Mean is $\mu=100$ and a standard deviation is $\sigma =15$ , then the variable $X\sim N(100,15^2)$ .

Use substitution

$Z=\dfrac{X-\mu}{\sigma},\\ \\ Z=\dfrac{X-100}{15}$ .

This substitution gives you that $Z\sim N(0,1)$ .

a. For X=130, $Z=\dfrac{130-100}{15}=2$ and $Pr(X>130)=Pr(Z>2) =0.9772$ (the decimal value is taken from the Standard Normal Distribution Table).

b. For X=90, $Z=\dfrac{90-100}{15}=-\dfrac{2}{3}$ and for X=110, $Z=\dfrac{110-100}{15}=\dfrac{2}{3}$ . Then $Pr(90$ (the decimal value is taken from the Standard Normal Distribution Table).