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mote1985 [20]
3 years ago
14

What is the next term for the given arithmetic sequence? -3, -2.25, -1.5, -0.75, ...

Mathematics
2 answers:
Rasek [7]3 years ago
5 0
0.  Each time you're adding 0.75, so adding -0.75+0.75=0!
Korolek [52]3 years ago
3 0
In this sequence a=-3
d=-2.25-(-3)
d=-2.25+3
d=0.75
So next term is 5th term so it is a+4d
=-3+4(0.75)
=-3+3
=0
So next term is 0
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3 0
3 years ago
Lydia writes the equation below with a missing value.
Alex73 [517]

If she puts 0 in the box she would have a direct variation.

Lydia writes the equation y = 5x - __ with a missing value.

She puts a value in the box and says that the equation represents a direct variation.

We have to choose the correct option from the given options that explain that the equation could represent a direct variation.

When two variables are such that one is a constant multiple of the other, we said they are in Direct variation.

<h3>What is the direct variation?</h3>

In form of y = ax, where y and x are in direct variation.

Consider the given equation y = 5x  - __

For the equation to be in direct variation the value of the missing term has to be 0.

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Option (a) is correct.

To learn more about the direct variation visit:

brainly.com/question/25215474

#SPJ1

3 0
2 years ago
Read 2 more answers
The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand
NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in  foreign language=0.20

The probability than an American CEO can not transact business in foreign language=1-0.20=0.80

Total number of American CEOs  chosen=12

a. The probability that none can transact business in a foreign language=12C_0(0.20)^0(0.80)^{12}

Using binomial theorem nC_r(1-p)^{n-r}p^r

The probability that none can transact business in a foreign language=\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}

b.The probability that at least two can transact business in a foreign language=1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))

c.The probability that all 12 can transact business in a foreign language=12C_{12}(0.8)^0(0.2)^{12}

The probability that all 12 can transact business in a foreign language=\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}

5 0
3 years ago
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