4 years ago

Solve the system by graphing.

Mathematics

1 answer:

nlexa [21]4 years ago

4 0

When solving a system by graphing you need to see where the lines intersect.

Below is a picture of these lines graphed. The green line is y = x +4 and the blue line is y = 4x - 1

The red dot represents the intersection is about (1, 5)

The original point is: (1.667, 5.667)

Hope this helped!

You might be interested in

What are the discontinuities of the function f(x) =x<2-36/4x-24 ?

kipiarov [429]

Well, 2-36/4x-24 is the same as (2-24)-(36/4)x which simplifies to -22-9x. This does not have a discontinuity anywhere. If you meant to divide 36 by 4x, then x=0 would be the discontinuity since you cannot divide by 0. If you meant to have 4x-24 all in the denominator, then x=6 is the discontinuity since that would make the bottom equal 0. So it seems you need some parenthesis here somewhere for your problem to make sense.

4 0

3 years ago

what are the values of a, b, and c in the quadratic equation 0 = x2 – 3x – 2? - a = , b = 3, c = 2 - a = , b = –3, c = –2 - a =

Dafna11 [192]

$x^2-3x-2=0\\\\a=1;\ b=-3;\ c=-2\\\Delta=b^2-4ac\\\\\Delta=(-3)^2-4\cdot1\cdot(-2)=9+8=17 \ \textgreater \ 0\\\\then\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{3-\sqrt{17}}{2\cdot1}=\boxed{\dfrac{3-\sqrt{17}}{2}}\\\\x_2=\dfrac{3+\sqrt{17}}{2\cdot1}=\boxed{\dfrac{3+\sqrt{17}}{2}}$