All categories

3 years ago

I have to solve the system of linear equations by elimination. i also have to check my solution.

Mathematics

1 answer:

Travka [436]3 years ago

6 0

Answer:

$x=1$ , $y=6$

Step-by-step explanation:

Give.

$x+2y=13$ ----------(1)

$-x+y=5$ ------------(2)

Solve this linear equation by elimination method.

Add equation 1 and 2

$x+2y=13$

$-x+y=5$

-----------------------------

$0+3y=18$

$3y=18$

$y=\frac{18}{3} \\y=6$

Put y value in equation 2

$-x+6=5$

$-x=5-6$

$-x=-1$

$x=1$

$x=1$ , $y=6$

You might be interested in

Find the number of possible outcomes in the sample space. The chess club must decide when and where to meet for a practice. The

Lesechka [4]

Solution

- The number of possible outcomes in the sample space is simply gotten by multiplying out all the events together.

- There are 3 possible days: Tuesday, Wednesday, or Thursday. Thus, there are 3 possible outcomes.

- There are 3 possible times: 3PM, 4PM, or 5PM. Thus, there are 3 possible outcomes again.

- There are also 9 possible classrooms available meaning another 9 possible outcomes.

- Thus, the total possible outcomes in the sample space is

$3\times3\times9=81\text{ possible outcomes}$

4 0

1 year ago

Which expressions have a value of 16/81? Check all that apply.

lana [24]

Which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

Answer:

First and last option is correct.

$(\frac{2}{3})^{4}=\frac{16}{81}$

$(\frac{4}{9})^{2}=\frac{16}{81}$

Step-by-step explanation:

Given:

There are four options.

(2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

We need to check all given options for value of 16/81.

Solution:

Using rule.

$(\frac{a}{b})^{n}=\frac{a^{n}}{b^{n}}$

Solve for option $(\frac{2}{3})^4$ .

$(\frac{2}{3})^{4}=\frac{2^4}{3^4}=\frac{2\times 2\times 2\times 2}{3\times 3\times 3\times 3}=\frac{16}{81}$

Solve for option $(\frac{16}{3})^4$ .

$(\frac{16}{3})^{4}=\frac{16^4}{3^4}=\frac{16\times 16\times 16\times 16}{3\times 3\times 3\times 3}=\frac{65536}{81}$

Solve for option $(\frac{4}{81})^2$ .

$(\frac{4}{81})^{2}=\frac{4^2}{81^2}=\frac{4\times 4}{81\times 81}=\frac{16}{6561}$

Solve for option $(\frac{4}{9})^2$ .

$(\frac{4}{9})^{2}=\frac{4^2}{9^2}=\frac{4\times 4}{9\times 9}=\frac{16}{81}$

Therefore, expression $(\frac{2}{3})^4$ and $(\frac{4}{9})^2$ have a value of $\frac{16}{81}$ .

6 0

3 years ago

The measures of the angles of a triangle are shown in the figure below. Solve for x.<br> 80°<br> 39

zloy xaker [14]

Answer:

61 degrees

Step-by-step explanation:

A triangle has a total of 180 degrees. We already know 80 and 39. 80+39 is 119. 180-119+61

7 0

3 years ago

Plz help me. But like for real plz

scoundrel [369]

Answer:

They will pay the same amount!

3 0

3 years ago

Read 2 more answers

In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a

Art [367]

Answer:

The answer is " $\bold{T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5}$ "

Step-by-step explanation:

Given value:

Temp-maximum= $18^{\circ}$

Temp. minimum = $3^{\circ}$

It is halfway between 10 am and 10 pm to 4 am.

The sinus and cosine roles could be used throughout the year to predict fluctuations in climate models. Its type of formula that can be used to model such information is:

$T = A \cos B(t-C) + D,$ where parameters are A, B , C, D, T is the ° C temperature and t is the time (1-24)

$A = amplitude = \frac{(T_{max} - T_{min})}{2}\\\\$

$= \frac{(3 - 18)}{2}\\\\= - \frac{15}{2}\\\\ = -7.5$

$B = \frac{2 \pi}{24}\\\\$

$= \frac{\pi}{12}$

$C = \text{ units translated to the right}= 4$

$D = y_{min} + amplitude = units \ translated \ up\\\\$

D = 7.5 + 3 = 10.5

Its trigonometric function equation that model temperature T hours after midnight in Johannesburg t.

$T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5$

6 0

4 years ago