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Jlenok [28]
3 years ago
5

Help please if your good at math

Mathematics
2 answers:
Crank3 years ago
8 0

Answer: The correct answer  is A.

The "point-slope" form of the equation of a straight line is:

y − y1 = m(x − x1)

So the answer is y-9=2(x-5)

Please mark as brainliest!! Thanks!

aleksandr82 [10.1K]3 years ago
4 0

The correct answer is A.

The point-slope form of the equation of a straight line is: y=y1=m(x-x1)

So the answer is y-9=2(x-5)

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Akira buys 10 tickets to a show. She also pays a $5 parking fee. If she spent $35 in total, how much did each ticket cost? Use x
Arte-miy333 [17]

Answer: Each ticket cost 3 dollars

Step-by-step explanation: First take 35 and subtract 5 which equals 30

then divide 30 by 10 and you get 3

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3 years ago
The probability that it will be at least 70°on Tuesday is 0.65. If it is at least 70°, there is a 0.8 chance that Mrs. Collins w
Zielflug [23.3K]
P(> or =70) =0.65
P(Collins inside) =0.80
P(not 70) = 1-P(70) =>0.35
P(Collins inside) = 0.1
Then P(70 AND Collin inside) .65 x .8 =0.52
P( not 70 AND Collin Outside = 0.35 x 0.1=0.035
TOTAL Possibility [(70 AND Inside) OR (not 70 AND Outside):
=0.52 + 0.034 =0.555


 

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3 years ago
The medical laboratory claim that the mean turn-around time for the performance of the battery of tests on blood sample is 1.005
Shkiper50 [21]

Answer:

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Step-by-step explanation:

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stira [4]

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3 years ago
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given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta
lapo4ka [179]

Answer:

\cos{\theta} = \frac{\sqrt{15}}{4}

Step-by-step explanation:

For any angle \theta, we have that:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

Quadrant:

0 \leq \theta \leq \frac{\pi}{2} means that \theta is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1

\frac{1}{16} + (\cos{\theta})^{2} = 1

(\cos{\theta})^{2} = 1 - \frac{1}{16}

(\cos{\theta})^{2} = \frac{16-1}{16}

(\cos{\theta})^{2} = \frac{15}{16}

\cos{\theta} = \pm \sqrt{\frac{15}{16}}

Since the angle is in the first quadrant, the cosine is positive.

\cos{\theta} = \frac{\sqrt{15}}{4}

3 0
3 years ago
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