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ratelena [41]
3 years ago
15

How do you find a percent of a number ? Ex. 8% of 90

Mathematics
2 answers:
Leni [432]3 years ago
7 0
Ciao! Look the picture ;)

musickatia [10]3 years ago
6 0
If you wanted to find 8 percent of 90 you would just multiply 90 by .08 and you would get your answer which would be 7.2
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allsm [11]

Answer:

there are 6 dogs

Step-by-step explanation:

x = dogs

x= 2 + 4

x = 6

8 0
3 years ago
Read 2 more answers
Please Help this is the only one i dont know!!
Stella [2.4K]

Answer:

\large\boxed{x=\dfrac{23}{33}}

Step-by-step explanation:

\text{Let}\ x=0.\overline{69}\\\\x=0.696969...\qquad\text{multiply both sides by 100}\\\\100x=69.696969...\qquad\text{subtract}\ x\ \text{from}\ 100x:\\\\100x-x=69.696969...-0.696969...\\\\99x=69\qquad\text{divide both sides by 99}\\\\x=\dfrac{69}{99}\\\\x=\dfrac{23}{33}

7 0
3 years ago
What is the nearest hundredth of 2.6666
Advocard [28]

2.66

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5 0
3 years ago
Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu
Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

y=x^4-10x^3+38x^2-64x+40

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))   ( ∵ (3-i) is the conjugate of (3+i) )

\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)

\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)

\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)

\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)

\Rightarrow y=(x^2-4x+4)(x^2-6x+10)

\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10

\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40

\Rightarrow y=x^4-10x^3+38x^2-64x+40

Therefore, this is the required polynomial function.


4 0
3 years ago
Thang decided to borrow ​$7000 from his local bank to help pay for a car. His loan was for 3 years at a simple interest rate of
slamgirl [31]

Answer:

$420

Step-by-step explanation:

8 0
2 years ago
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