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Dima020 [189]
4 years ago
14

Olaf has 250 files on an external hard drive. Of those files, 12% are photos.

Mathematics
1 answer:
Inessa05 [86]4 years ago
4 0
A. x/250 = 12/100
   250 x 12 = 3,000
  3,000/100 = 30
B. 30
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Pick one please and thank u
valina [46]
The second one because the answer to the first one is a two digit number and the answer to the second is a one digit number, so #2 only uses two 2-digit numbers
8 0
3 years ago
A chain letter works as follows: One person sends a copy of the letter to five friends, each of whom sends a copy to five friend
Svetach [21]

Answer:

The number of  people that received copies of the letter at the twentieth stage is<em> 9.537 × 10¹³ </em>.

Step-by-step explanation:

Using the discrete model,

a_k = r a_(k-1) for all integers k ≥ 1 and a₀ = a

then,

aₙ = a rⁿ for all integers n ≥ 0

Let a_k be equal to the number of people who receive a copy of the chain letter at a stage k.

Initially, one person has the chain letter (which the person will send to five other people at stage 1). Thus,

a = a₀ = 1

The people who received he chain letter at stage (k - 1),  will send a letter to five people at stage k and thus per person at stage (k - 1), five people will receive the letter. Therefore,

a_k = 5 a_(k - 1)

Thus,

aₙ = a rⁿ = 1 · 5ⁿ = 5ⁿ

The number of  people that received copies of the letter at the twentieth stage is

<em>a₂₀ = (5)²⁰ = 9.537 × 10¹³ copies</em>

5 0
3 years ago
Write the equation of the line perpendicular to y=-1/4x-7 that passes through the point (3,-2)
leva [86]

Step-by-step explanation:

the equation of line is given by;

y-y1=m(x-x1)

7 0
3 years ago
Please help
Ipatiy [6.2K]
The answer is c hope it helps:)
3 0
3 years ago
Identify the quotient in the form a + bi. HELP ASAP PLEASE!!
Artist 52 [7]

Solving \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

Option A is correct.

Step-by-step explanation:

We need to find the result of \frac{4-5i}{2+3i}

We need to remove i from the denominator. For removing i Multiplying and dividing by 2-3i:

\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}

Solving:

=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i*(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,i^2=-1\\=\frac{8-12i-10i+15(-1))}{4-9(-1)}\\=\frac{8-12i-10i-15}{4+9}\\=\frac{8-15-12i-10i}{13}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}

So, solving \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

  • brainly.com/question/10736268
  • brainly.com/question/4678474

#learnwithBrainly

5 0
3 years ago
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