Question

Which function can be used to model the graphed geometric sequence?

Answer 1

Answer: The correct option is 1, i.e., $f(x+1)=\frac{5}{6}f(x)$.

Explanation:

The geometric sequence is in the form of,

$a,ar,ar^2,ar^3,....$

Where, a is the first term of the sequence and r is the common ratio of the sequence.

It means the $n_{th}$ term of the sequence is defined as,

$a_n=ar^{n-1}$

So the the $(n+1)_{th}$ term of the sequence is defined as,

$a_{n+1}=ar^n$

$a_{n+1}=r(ar^{n-1})$

$a_{n+1}=ra_n$

It means the geometric sequence is in the form of,

$f(x+1)=rf(x)$

Where, r be any constant.

From the options only $f(x+1)=\frac{5}{6}f(x)$ is in the form of $f(x+1)=rf(x)$ with common ratio $\frac{5}{6}$.

Therefore, the function can be used to model the graphed geometric sequence is $f(x+1)=\frac{5}{6}f(x)$ .

Answer 2

A - f(x + 1) = ⅚ f(x)

Step-by-step explanation:

Right on the edge final!

I hope this helps!

- sincerelynini