Answer:
No, the conditions for normality have not been met because the sample size for the quarters is not large enough and no information is given about the distributions of the populations.
Step-by-step explanation:
"The Kolmogorov-Smirnov test (K-S) and Shapiro-Wilk (S-W) test are designed to test normality by comparing your data to a normal distribution with the same mean and standard deviation of your sample. If the test is NOT significant, then the data are normal, so any value above .05 indicates normality"
Answer: Do you have a picture of the questions??
Step-by-step explanation:
= 16 + 49 - 3(11) - 4(10)
= 16 + 49 - 33 - 40
= -8
First solve for the slope, m using the two points given. It doesn't matter which point you choose as point 1 or 2 as long as you're consistent.
m = (y2 - y1)/(x2 - x1)
point 1: (–6.4, –2.6)
point 2: (5.2, 9)
m = (9 - -2.6)/(5.2 - -6.4)
m = (9 + 2.6)/(5.2 + 6.4)
m = 11.6/11.6
m = 1
put the newly found slope into the linear equation for m
y = (1)x + b
y = x + b
Now solve for the y-intercept, b
by putting one of the given points
9 = 5.2 + b
b = 9 - 5.2
b = 3.8
final equation:
y = x + 3.8
Answer c because .10 x 40 equals 4 plus 2
