Answer:
x
≤
13
Step-by-step explanation:
hope this helps
Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
I think its 1 on the graph correct me if im wrong
Answer: 28
Step-by-step explanation:
add them all of them up then simply subtract 46 from 18 and youll get your final answer which is 28
hope this helps :)
Two angles that have the sum of 180 degrees are supplementary angles. If you need to find angle A, you just need to subtract angle B from 180 degree to find out the degree of the particular angle. Hope I helped.