Answer:
Take
as the projection of u onto v and
as the vector such that b+w =u
Step-by-step explanation:
The formula of projection of a vector u onto a vector v is given by
, where
is the dot product between vectors.
First, let b ve the projection of u onto v. Then
![b = \frac{u\cdot v}{v\cdot v}v= \frac{-6\cdot 7+8\cdot 1}{7\cdot 7+1\cdot 1}(7,1) = \frac{-34}{50}(7,1) = \frac{-17}{25}(7,1)](https://tex.z-dn.net/?f=b%20%3D%20%5Cfrac%7Bu%5Ccdot%20v%7D%7Bv%5Ccdot%20v%7Dv%3D%20%5Cfrac%7B-6%5Ccdot%207%2B8%5Ccdot%201%7D%7B7%5Ccdot%207%2B1%5Ccdot%201%7D%287%2C1%29%20%3D%20%5Cfrac%7B-34%7D%7B50%7D%287%2C1%29%20%3D%20%5Cfrac%7B-17%7D%7B25%7D%287%2C1%29)
We want a vector w, that is orthogonal to b and that b+w = u. From this equation we have that w = u-b = (-6,8)-\frac{-17}{25}(7,1)= \frac{1}{25}(-31,217)[/tex]
By construction, we have that w+b=u. We need to check that they are orthogonal. To do so, the dot product between w and b must be zero. Recall that if we have vectors a,b that are orthogonal then for every non-zero escalar r,k the vector ra and kb are also orthogonal. Then, we can check if w and b are orthogonal by checking if the vectors (7,1) and (-31, 217) are orthogonal.
We have that
. Then this vectors are orthogonal, and thus, w and b are orthogonal.