Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
The answer is the SAS postulate. The two triangles have two pairs of corresponding, congruent sides, and the included angles are congruent. And thus, triangles XYZ and ABC are congruent by the SAS postulate.
Well, let's write it out, shall we?
6c2-5d+8
Now plug in the numbers.
6(5^2)2-5(4)+8
Now simplify using PEMDAS
Parentheses
Exponents
Multiplication
Division
Addition and Subtraction (They go together go from left to right in the equation)
5^2= 5*5 = 25
6 * 25 = 150
150 * 2 = 300
5 * 4 = 20
Rewrite the equation.
150-20+8
Use PEMDAS again ( refer to the previous mentioning)
150 - 20 = 130
130 + 8 = 138
Answer:
135
Step-by-step explanation:
15x18/2=135
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