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2 years ago

Find the surface area of a cylinder

Mathematics

1 answer:

jeka57 [31]2 years ago

8 0

Answer:

(REDACTED)

Step-by-step explanation:

First find the area of the circle on top using (REDACTED). Then multiply it by the (REDACTED) then you get the simple answer of (REDACTED).

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Someone please help!!! Look at the attachment

julsineya [31]

Answer:

1. $\angle 5$ and $\angle 13$ are Corresponding Angles

2. $\angle 4$ and $\angle 9$ are Alternate Interior Angles

3. $\angle 5$ and $\angle 16$ are Alternate Exterior Angles

4. $\angle 3$ and $\angle 9$ are Consecutive Interior Angles

Step-by-step explanation:

Alternate Interior Angles - When a pair of angles are in the interior in the opposite sides of the transversal.

Alternate Exterior Angles -When a pair of angles are in the outside in opposite sides of the transversal.

Corresponding Angles - When a pair of angles are in the same side of one of two sides by a cross-section.

Consecutive Interior Angles - When a pair of angles on the side are same but inside the two lines.

8 0

3 years ago

School band sold 30 raffle tickets each ticket is labeled with a number 1 to 31 winning ticket will be drawn what is the probabi

Setler [38]

Answer:

0.27

Step-by-step explanation:

To solve this problem, we will use Set Theory Approach to Probability.

Let U = the Sample Space which consists of all possible tests.

Of course U = {1,2,3 .... ,30}

So, no elements in that.

U = n = 30

Let Q = the event bearing a multiple of 4 No winning ticket, and,

R = the case that has the No. 19 winning ticket

∴

Q = { 4, 8, 12 , 16 , 20, 24 , 28} , and

R = {19} , so that

Q ∩ R = ϕ

P(Q ∩R ) = 0

As, n(Q) = 7 , n(R) = 1 , we have,

P (Q) = $\frac{n (A)}{n(U)}$ = $\frac{7}{30}$ , and P (R) = $\frac{1}{30\\}$

P (Q∪R) = P(Q ) + P(R) − P(A∩B) = $\frac{7}{30}$ + $\frac{1}{30\\}$ − 0 = $\frac{8\\}{30\\}$

≅ 0.27 .

4 0

2 years ago

A fisherman can row upstream at 4 mph and downstream at 6 mph. He started rowing upstream until he got tired and then rowed down

shepuryov [24]

A fisherman can row upstream at 4 mph and downstream at 6 mph. He started rowing upstream until he got tired and then rowed downstream to his starting point. The distance of how far the fisherman row if the entire trip took 2 hours is 9.6 miles

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The speed of an object refers to the change of the object's distance within a specified time.

Mathematically, we can have;

$\mathbf{Speed =\dfrac{distance}{time}}$

Distance = speed × time

From the information given;

The fisherman row upstream for 4 miles/ hour.
The distance covered by the fisherman = 4 × t₁ ----- (1)

The fisherman row downstream at 6 miles/ hour

The distance covered by the fisherman = 6 × t₂ ------ (2)

SInce it took the entire trip 2 hours, we can infer that:

t₁ + t₂ = 2
t₂ = 2 - t₁

From equation (2), replace the above value of t₂ into equation (2)

d = 6 t₂
d = 6(2 - t₁)
d = 12 - 6t₁

From equation (1)

d = 4 t₁

Equation both distance together, we have:

12 - 6t₁ = 4t₁
12 = 4t₁ + 6t₁
12 = 10t₁
t₁ = 12/10
t₁ = 1.2 hours

From t₂ = 2 - t₁

t₂ = 2 - 1.2
t₂ = 0.8 hours

From d = 4t₁

Replace t₁ with 1.2 hours

d = 4(1.2 hours)
d = 4.8 miles

Also, from d = 6t₂

d = 6(0.8)
d = 4.8 miles

Therefore, we can conclude that the distance of how far the fisherman row if the entire trip took 2 hours is (4.8+4.8) miles = 9.6 miles

Learn more about distance here:

brainly.com/question/12319416?referrer=searchResults

3 0

2 years ago

A circular cylindrical container, open at the top, and having a capacity of 24pi cubic inches, is to be manufactured. If the cos

otez555 [7]

Answer: radius r = 2 inches

height h = 6 inches

Step-by-step explanation:

Given;

Volume V = 24πin3

Volume of a cylinder is given by

V = πr^2h

h = V/πr^2. ....1

Where, h = height and r = radius of cylinder

For the surface area of the cylinder with open top. we have,

S = 2πrh + πr^2

For the cost of materials used, let k represent the cost of materials used for the body of the cylinder.

Then, for the bottom will be 3k

Total cost will be represented by C, which gives

C = 2πrhk + 3πr^2k. .....2

Substituting eqn 1 to 2, we have;

C = 2πrVk/πr^2 + 3πr^2k

C = 2Vk/r + 3πr^2k

The material cost is minimum at dC/dr = 0

dC/dr = -2Vk/r^2 + 6πrk =0

6πrk = 2Vk/r^2

r^3 = 2V/6π

r = (2×24π/6π)^-3

r = (8)^-3

r = 2

Substituting r = 2 into eqn1

h = 24π/π(2^2)

h = 24/4 = 6

h = 6

5 0

3 years ago

What is the answer for the diagram?

Westkost [7]

Answer:

1340-

Step-by-step explanation:

5 0

2 years ago