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The volume of an oblique pyramid with a square base is V units3 and the height is h units. Which expression represents the area

givi [52]

Answer:

Area of the base of the pyramid = V/h

Step-by-step explanation:

Mathematically, we know that the volume of the pyramid can be calculated by multiplying the area of the base by the height of the pyramid

Now using the variables in the question;

V = area of base * height of pyramid

Area of base = V/height of pyramid

Area of base = V/h

3 1

3 years ago

The concentration of a drug in an organ at any time t (in seconds) is given by

-Dominant- [34]

Answer:

The concentration of a drug in an organ at any time t (in seconds) is given by s 0.25t - 15(1 - e-t/60) if osts 20 | 15e-t/60 – 10e-(t - 20)/60 if t> 20 where c(t) is measured in milligrams per cubic centimeter (mg/cm3). (a) What is the initial concentration of the drug in the organ? 0 mg/cm3 (b) What is the concentration of the drug in the organ after 14 sec? (Round your answer to three decimal places.) x mg/cm3 38 (c) What is the concentration of the drug in the organ after 40 sec? (Round your answer to three decimal places.) mg/cm3 Need Help? | Read It

7 0

2 years ago

What is the value of n in the equation ? n = 0 n = 2 n = 4 n = 6

RideAnS [48]

Answer:

N=2

Step-by-step explanation:

N=2

5 0

3 years ago

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The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Alchen [17]

Answer:

Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

Let X = number of hours spent per week on household chores

So, assuming data follows normal distribution; X ~ N( $\mu=28,\sigma^{2}=7^{2}$ )

The z score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = mean hours = 28

$\sigma$ = standard deviation = 7 hours

n = sample of adults = 49

Let $\bar X$ = sample mean hours spent per week on household chores

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P( $\bar X$ > 26.75 hours)

P( $\bar X$ > 26.75 hours) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{26.75-28}{\frac{7}{\sqrt{49} } }$ ) = P(Z > -1.25) = P(Z < 1.25)

= 0.89435 {using z table}

Therefore, probability that the mean hours spent per week on household chores is more than 26.75 is 0.89435.

4 0

3 years ago

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15 yards to 18 yards increase or decrease

dlinn [17]

This is an increase of 3 yards.

3 0

3 years ago

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