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3 years ago

The floor area of a hall is 1044 m2. The length is 36 m. Give a quick estimate of width of the hall. ?

Mathematics

1 answer:

wolverine [178]3 years ago

4 0

36m. Im not sure but thats what i got, hope it helps...

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If one bottle of the national brand of cough medicine costs $12, what is the cost of a bottle of the store brand if its 2/3 of t

skad [1K]

The answer is $8, sense 12÷3×2=4×2=8.

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3 years ago

The product of a number and 4 increased by 7 is 5. What is the number?

yanalaym [24]

Answer: x = -1/2 = -0.5

Step-by-step explanation:

set up an equation

4x + 7 = 5 subtract 7 from both sides

4x = - 2 divide both sides by 4

x = -2/4

x = -1/2 = -0.5

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3 years ago

PLSSSS HELP Choose ALL answers that describe the polygon.

ipn [44]

Answer:

RSTU is a parallelogram, quadrilateral, rectangle, rhombus, and square. NOT trapezoid.

Step-by-step explanation:

The shape has four sides, so it's a quadrilateral.

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4 0

2 years ago

98 Points! Answer Quick!

timama [110]

Reason:

2. SD ⊥ HT. ∴ ∠SDH = ∠SDT =90°

3. Given (It is given in the question)

5. RHS congruence

(Here, the right angle, hypotenuse and one side of ΔSHD is congruent to that of ΔSTD).

Statement:

4. Line segment SD = SD

(Reflexive property is used to prove congruence of triangles. This property is used when an angle or line segment is congruent to itself.)

7 0

3 years ago

Read 2 more answers

part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.

Nat2105 [25]

Answer: $\bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}$

Step-by-step explanation:

Pythagorean Theorem is: a² + b² = c² , where "c" is the hypotenuse

$9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}$

Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12

$10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}$

Note: 12² + opposite² = 20² → opposite = 16

$11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$

Note: adjacent² + 7² = (13√2)² → adjacent = 17

5 0

3 years ago