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pentagon [3]
3 years ago
12

If 2 pizzas cost $16.22 how much would one cost

Mathematics
2 answers:
koban [17]3 years ago
6 0
16.22 divided by 2 = your answer. (8.11)
Naddika [18.5K]3 years ago
5 0
To find the answer you would have to divide 16.22 and 2 which would equal 8.11
You might be interested in
Find three real numbers​ x, y, and z whose sum is 6 and the sum of whose squares is as small as possible. g
mart [117]
We're minimizing x^2+y^2+z^2 subject to x+y+z=6. Using Lagrange multipliers, we have the Lagrangian

L(x,y,z,\lambda)=x^2+y^2+z^2+\lambda(x+y+z-6)

with partial derivatives

\begin{cases}L_x=2x+\lambda\\L_y=2y+\lambda\\L_z=2z+\lambda\\L_\lambda=x+y+z-6\end{cases}

Set each partial derivative equal to 0:

\begin{cases}2x+\lambda=0\\2y+\lambda=0\\2z+\lambda=0\\x+y+z=6\end{cases}

Subtracting the second equation from the first, we find

2x-2y=0\implies x=y

Similarly, we can determine that x=z and y=z by taking any two of the first three equations. So if x=y=z determines a critical point, then

x+y+z=3x=6\implies x=y=z=2

So the smallest value for the sum of squares is 2^2+2^2+2^2=12 when (x,y,z)=(2,2,2).
8 0
3 years ago
A major airline is concerned that the waiting time for customers at its ticket counter may be exceeding its target average of 19
sertanlavr [38]

Answer:

a) Statement is true

b) Statement incorrect. Company goal is to attend customer at 190 second at the most. So test should be one tail test  (right)

c) We have to reject H₀, and differences between sample mean and the hypothesized population mean should not be attributed only to sampling error

Step-by-step explanation:

a)  as the significance level is = 0,02  that means  α = 0,02 (the chance of error type I )  and the β (chance of type error II   is

1  -  0.02  =  0,98

b) The company establishe in 190 seconds time for customer at its ticket counter (if this time is smaller is excellent ) company is concerned about bigger time because that could be an issue for customers. Therefore the test should be a one test-tail to the right

c) test statistic

Hypothesis test should be:

null hypothesis                H₀   =  190

alternative hypothesis    H₀   >  190

t(s)  =  ( μ  -  μ₀ ) / s/√n      ⇒   t(s)  = ( 202 - 190 )/(28/√100 )

t(s)  = 12*10/28

t(s)  = 4.286

That value is far away of any of the values found for 99 degree of fredom and between  α  ( 0,025 and 0,01 ). We have to reject H₀, and differences between sample mean and the hypothesized population mean should not be attributed only to sampling error

If we look table  t-student we will find that for 99 degree of freedom and α = 0.02.

3 0
3 years ago
225.286 rounded to hundredths on a numberline
Schach [20]
Well if rounding it to the tenths is 230 then you would round back down to 200
3 0
3 years ago
Read 2 more answers
Using the formula F=9/5C+32, find C when F= 75.
den301095 [7]

Answer:

DIVIDING 9 AND 5 = 23.8

9/5 FRACTION = 0.04

Step-by-step explanation:

If 9/5 means 9 divided by 5

FLIP THE EQUATION

9/5C + 32 = 75

9/5C + 32 - 32 = 75 -32

9/5C = 43

9/5 = 1.8

1.8C = 43

1.8C/1.8 = 4

If 9/5 means 9/5ths fraction

FLIP THE EQUATION

9/5C + 32 = 75

9/5C + 32 - 32 = 75 -32

9/5C = 43

9/5C / 9/5 = 43 / 9/5

C = 0.04

Hope this helps i thought 9/5 was 9 divide by 5. If it was 9/5 as a fraction i also made that equation too.

7 0
3 years ago
−3/8 ÷ 1/2= the numbers are fractions
marishachu [46]

\text {Hi! To solve this problem you must...}

\text {Do Keep Change Flip (KCF):}

\text {Keep: -3/8}

\text {Change: /  into *}

\text {Flip: 1/2 into 2/1}

\text {Your new problem should be -3/8*2/1}

\text {The Final Step is to Multiply:}

\text {Note: When Multiplying Fractions you multiply Numerator by Numerator}

\text {and Denominator by Denominator}

\text {-3/8*2/1=}

\fbox {-6/8}

\text {Best of Luck!}

\text {-LimitedX}

4 0
3 years ago
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