Answer:
1. About 1/5 chance that Mary is chosen
About 1/7 chance John is chosen
2. about 0.0286 chance mary is chosen
about 0.0154 chance john is chosen
same as answer 2
Step-by-step explanation:
1. If you do proportions, a female's chance comes to 1/5 and a male's chance comes to 1/7.
2. for females, do 1/35 and males do 1/65
same as answer 2
Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°
<u>Step-by-step explanation:</u>
Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL
KM ≅ LM
3x + 23 = 7x - 37
23 = 4x - 37
60 = 4x
15 = x
KM = LM = 3x + 23
= 3(15) + 23
= 45 + 23
= 68
KL = 9x - 40
= 9(15) - 40
= 135 - 40
= 95
Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.
- Since N is the midpoint of KL and KL = 95, then NL = 47.5
- Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse
Use trig to solve for ∠L (which equals ∠K):
cos ∠L = 
cos ∠L = 
∠L = cos⁻¹ 
∠L = 45.7
Triangle sum Theorem:
∠K + ∠L + ∠M = 180°
45.7 + 45.7 + ∠M = 180
91.4 + ∠M = 180
∠M = 88.6
Answer:
10.75 would be a 64 ring size in the US
Answer: The correct answer is option B: There are between 15 and 20 green pieces in all 5 packages
Step-by-step explanation: The most important factor has been given which is, "Which statement about the candy pieces in the remaining packages is best supported by this information."
The information given is such that, the first package she opened had 4 green pieces and on this basis we can safely assume that all other packages have 4 green pieces as well. The second package had 3 green pieces and this based on this too we can safely assume that all other packages had 3 green pieces. Hence, all 5 packages can either have a total of 4 x 5 green candies which equals a total of 20 green pieces or, all 5 packages can have a total of 3 x 5 green candies which equals a total of 15 green pieces.
So according to Suzi's experiment, there are between 15 and 20 green pieces in all 5 packages.
Answer:
y=3
Step-by-step explanation:
(i used point-slope form which is (y1-y2)=m(x1-x2))
(10-y)=7(4-3)
10-y=7
-y=-3
y=3
