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ANEK [815]
3 years ago
10

Each side of the square below is 8 inches.

Mathematics
2 answers:
KatRina [158]3 years ago
6 0

Answer:

6 percent

Step-by-step explanation:

evablogger [386]3 years ago
5 0

Answer:

16%

Step-by-step explanation:

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What is the distance between the points (-30,10and(30,19) in the xy-plane
Alex787 [66]

Answer:

√3681

Step-by-step explanation:

D= √(30+30)^2+(19-10)^2

D= √60^2+9^2

D= √3600+81

D= 3681

5 0
3 years ago
This table reflects the result of a survey conducted in a town to find out the number of cars of a particular color.
inysia [295]

the range that would be the most appropriate to represent the numerical data on the vertical axis is B. 20 to 100.

<h3>what range would be most appropriate?</h3>

the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.

this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.

find out more on bar graph ranges at brainly.com/question/25196929.

#SPJ1

6 0
1 year ago
Any help would be great
Ad libitum [116K]

Answer:

88/57

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
IF P(A)=1/3, P(B)=2/5, and P(AuB)=3/5, what is P(A^B)?
Bumek [7]

The probability of the union of two events is the sum of their probability, minus the probability of their interserction:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

If we plug the known values into this formula, we have

\dfrac{3}{5} = \dfrac{1}{3} + \dfrac{2}{5} - P(A\cap B)

From which we can deduce

P(A\cap B) = \dfrac{1}{3} + \dfrac{2}{5} - \dfrac{3}{5} = \dfrac{2}{15}

So, the probability of A \setminus B is a bit less than P(A), we have to take away all events that belong to B as well:

P(A \setminus B) = P(A) - P(A\cap B) = \dfrac{1}{3} - \dfrac{2}{15} = \dfrac{1}{5}

3 0
3 years ago
8th term of 1/4,1/8,1/16,1/32
sukhopar [10]
a_1=\dfrac{1}{4};\ a_2=\dfrac{1}{8};\ a_3=\dfrac{1}{16};\ a_4=\dfrac{1}{32};...\\\\it's\ a\ geometric\ sequence\ where\ a_1=\dfrac{1}{4}\ and\ r=\dfrac{1}{8}:\dfrac{1}{4}=\dfrac{1}{2}\\\\a_n=a_1r^{n-1}\\\\n=8\\\\a_8=\dfrac{1}{4}\cdot\left(\dfrac{1}{2}\right)^{7-1}=\dfrac{1}{4}\cdot\left(\dfrac{1}{2}\right)^6=\dfrac{1}{4}\cdot\dfrac{1}{64}=\dfrac{1}{256}
4 0
2 years ago
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