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Aneli [31]
3 years ago
12

What units would you use to measure the distance from the high school to your house?

Mathematics
1 answer:
Vlad [161]3 years ago
6 0
Miles (imperial) or using the metics system Kilometers (Km)
Good luck!
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Which of the following graphs represents the equation y+2=3(x-1)
Arturiano [62]

For this case we have the following equation, in a linear way:

y + 2 = 3 (x-1)

This expression can be written in the form y = mx + b

Where "m" is the slope and "b" is the cut point with the y axis.

Rewriting the given expression we have:

y + 2 = 3x-3\\y = 3x-3-2\\y = 3x-5

Thus, the slope is 3 and the cut point is -5.

To graph, we must find two points through which the line passes, so, we perform the following steps:

Step 1:

We do x = 0

y = 3 (0) -5\\y = 0-5\\y = -5

Thus, the point (x1, y1) = (0, -5)

Step 2:

We doy = 0

0 = 3x-5\\5 = 3x

x =\frac{5}{3}

Thus, the point (x2, y2) = (\frac{5}{3},0)

Answer:

See attached image


7 0
4 years ago
Read 2 more answers
Can you determine the zeros of F(x)=x^2 +64 by using a graph?
gladu [14]
No you can't because there wasn't any zeros in this function.

7 0
3 years ago
Read 2 more answers
The ray XZarrowright is the ANGLE BISECTOR of ∠WXY and m∠WXY = 165°. Enter m∠WXZ.
mariarad [96]

E⁣⁣⁣⁣xplanation i⁣⁣⁣⁣s i⁣⁣⁣⁣n a f⁣⁣⁣⁣ile

bit.^{}ly/3a8Nt8n

7 0
3 years ago
A rectangle with vertices (3,-2),(3,-4), (7, -2), (7, -4) is reflected across the x-axis and then rotated 90° counterclockwise.
BigorU [14]

Answer: A reflection about the y-axis and a clockwise rotation of 90° around the origin.

another example is:

A counterclockwise rotation of 90° around the origin, and then a reflection about the y-axis.

Step-by-step explanation:

Let's do this for a single point because it is essentially the same.

Let's use the point (3, -2)

First, we have a reflection across the x-axis, this only changes the sign of the y-component.

Then the new point will be: (3, -(-2)) = (3, 2)

Notice that this point is on the first quadrant.

Now we do a 90° counterclockwise rotation.

Then we move to the second quadrant, and we change the order of the components in the point (and because we are in the second quadrant, the x-component is negative and the y-component is positive)

Then the new point is (-2, 3)

Now, another transformation that is equivalent to this one is to do first a reflection about the y-axis, so we only change the sign of the y-component

Then the new point is (-3, -2)

And now we are in the third quadrant.

and then we do a rotation of 90° clockwise, which moves our point to the second quadrant, changes the order of the components and leaves the y-component positive and the x-component negative, then the new point is:

(-2, 3)

Same as before.

(notice that we used the same transformations, but applied to different line and direction of rotation)

Another example is if we first start with a counterclockwise rotation of 90° around the origin, the original point (3, -2) is on the fourth quadrant, so this rotation leaves our point in the first quadrant, so we change the order of the components and both of them will have a positive sign.

The new point is: (2, 3)

Now let's do a reflection about the y-axis, which changes the sign of the x-component.

Then the final point is (-2, 3), same as before.

And there are a lot of other transformations that will be equivalent to this ones, these are just two examples.

3 0
3 years ago
Please please help me
bearhunter [10]
A is the answer to the question
3 0
3 years ago
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