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Marina CMI [18]
4 years ago
11

The three classes of rocks are sedimentary, metamorphic, and igneous. How are rocks classified into one of these three groups?

Physics
1 answer:
sattari [20]4 years ago
7 0

Answer:

according to the method of their formation

Explanation:

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The acceleration due to gravity on the moon is 1.6 m/s2. What is the gravitational potential energy of a 1200-kg lander resting
faltersainse [42]

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The equation for gravitational potential energy is GPE = mgh. 


GPE = 1200(1.6)(350) = 672000 J


Hope this answers the question. Have a nice day.

5 0
3 years ago
Read 2 more answers
A pendulum has 968 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
Black_prince [1.1K]
968 j or kg because it cannot lose any of it energy and cannot gain any extra mass from nothing
8 0
3 years ago
Make vector A on the simulation have a magnitude of exactly 10 units. What were the starting points and ending points of your ve
Gwar [14]

Answer:

Making a vertical vector, we have a starting point at (-5,2) and an end point at (5,2) that will give us a vector of magnitude of 10 units.

Explanation:

In order to make vectors that have a magnitude of 10 units, the distance between the starting and ending points must be equal to 10.

The easiest way is to set points on either an horizontal or vertical line to make horizontal or vertical vectors.

We can have starting point at (-5,2) and  then move up 10 units so we will be at the ending point (5,2), thus the distance between them is 10 units so the vector has a magnitude of 10 units.

We can verify that using the formula for the magnitude which requires first to find the vector.

\vec v = \text{End point } - \text{Start point}

So for the points we have

\vec v = (5,2)-(-5,2)

We can work with each component, for the x component we have 5-(-5) which give us 10 and for the y component we have 2-2  which give us 0, so the vector is

\vec v =

Thus its magnitude is

|v|= \sqrt{v_x^2+v_y^2}\\|v|= \sqrt{10^2+0^2}\\|v|=\sqrt{100}\\|v|=10

Thus we have verified our vector has a length 10.

7 0
4 years ago
The surface of a mirror is flat.
tia_tia [17]
True great job
Have a great day

3 0
3 years ago
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Our textbook describes a common model for friction (both static and kinetic) in which the area of contact between interacting su
Mkey [24]

Contact area is not a factor of the amount of friction force acting between two bodies in contact, preventing rolling or sliding

Reasons:

  • Friction force is the product of the normal reaction and the coefficient of friction.
  • The coefficient of friction is higher in softer tires than hard tires which are required to be wider to reduce the pressure that can cause deformation withstood by hard tires.
  • The wide tires in drag racing cars can be thought of being made from the soft compound tire material having a higher coefficient of friction that increases the friction force.

Other advantages of wide tires are;

  • Increased traction
  • Shorter stopping distance

Learn more here:

brainly.com/question/17209968

7 0
3 years ago
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