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noname [10]
3 years ago
14

A 5.0-kg mass with an initial velocity of 4.0 m/s, east collides with a 4.0-kg mass with an initial velocity of 3.0 m/s, west. a

fter the collision the 5.0-kg mass has a velocity of 1.2 m/s, south. what is the magnitude of the velocity of the 4.0-kg mass after the collision?
Physics
1 answer:
Andre45 [30]3 years ago
4 0
Dude i wish i knew sorry
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Who was Georges Lemaitre and how did he contribute to the Big Bang theory?<br> (15 points)
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A Belgian Astronomer and Cosmotologist who formulated the modern Big Bang theory, which states that the universe began in a cataclysmic explosion of a small, primeval “super-atom”
7 0
3 years ago
Confused..................
svlad2 [7]
1. Dump the container out.
2. Sift the large items out until the sugar and gravel is by itself.
3. Continue separating the other items.
3 0
3 years ago
An unknown material, m1 = 0.45 kg, at a temperature of T1 = 91 degrees C is added to a Dewer (an insulated container) which cont
goldenfox [79]

Answer:

Explanation:

Let the specific heat of material be s

heat lost by material = m₁ s (T 1 - T ) ,  (T 1 - T ) is fall in temp , m₁ is mass of material

= .45 x s x (91 - 31.4 )

= 26.82 s

Heat gained by water

= m₂ cw (T2 - T )

1.3 x 4186 x ( 31.4 - 23 )

heat lost = heat gained

m₂ cw (T2 - T ) = m₁ s (T 1 - T )

1.3 x 4186 x ( 31.4 - 23 ) =  .45 x s x (91 - 31.4 )

45711.12 = 26.82 s

s = 1704.36

7 0
4 years ago
Consider a metal single crystal oriented such that the normal to the slip plane and slip direction are at angles of 60° and 35°,
Vedmedyk [2.9K]

Answer:

19.5324 MPa

Explanation:

Information provided

Angle between the normal to the slip plane with tensile axis, \alpha=60^{o}&#10;

Angle by slip direction with tensile axis, \beta=35^{o}

Critical resolved shear stress, \tau_{c}=8 MPa

Applied stress \sigma=12 MPa

Shear stress at slip plane

\tau=\sigma cos\alpha cos\beta

\tau=12cos60^{o}cos35^{o}=4.915 MPa

\tau hence crystal won’t yield

Applied stress, \sigma for crystal to yield is given by

\sigma=\frac {\tau_{c}}{cos\alpha cos\beta}

\sigma=\frac {8}{cos60cos35}=19.53239342 MPa

\sigma=19.5324 MPa&#10;

7 0
3 years ago
Help me with this please
Jobisdone [24]

Answer:

Option D- 1,2 and 3

Explanation:

Gravity always acts on an object irrespective of height

4 0
3 years ago
Read 2 more answers
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