Answer:
Explanation:
B- The red horse's average speed was greater than the black horse's average speed.
Red average speed = 1/120 = 0.00833 mi/s
Black average speed = 1/150 = 0.00667 mi/s
we only know about average speed based on the information given. Either horse could have had higher or lower, even negative, instantaneous speed during some phase of the race.
According to the solving, the volume that this gold nugget occupies is 1.29 cm³.
<h3>What is volume?</h3>
Volume is a standard measure of three-dimensional space that is occupied. It is typically mathematically represented using standard or SI-derived units. Volume and the concept of length are connected. It is sometimes referred to as the object's capacity.
d= m/ V
m= dV
V= m/d
<h3>So according to the given data,</h3>
The mass of the gold nugget is 25 grams.
The density of gold is 19.32 g/cm³.
We know that,
m= Vd
To find out the Volume(V),
V= m/d
V= (25 g)/(19.32 g/cm³)
V= 1.29 cm³.
According to the solving, the volume this gold nugget occupies is 1.29cm³.
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Answer:
22145.27733 ft
124984.76055 ft
Explanation:
The equation of pressure is
where,
=Atmospheric pressure = 800 mbar
k = Constant
h = Altitude = 35000 ft
Now
The altitude will be 22145.27733 ft
The elevation is 124984.76055 ft
If an icy surface means no friction, then Newton's second law tells us the net forces on either block are
• <em>m</em> = 1 kg:
∑ <em>F</em> (parallel) = <em>mg</em> sin(45°) - <em>T</em> = <em>ma</em> … … … [1]
∑ <em>F</em> (perpendicular) = <em>n</em> - <em>mg</em> cos(45°) = 0
Notice that we're taking down-the-slope to be positive direction parallel to the surface.
• <em>m</em> = 0.4 kg:
∑ <em>F</em> (vertical) = <em>T</em> - <em>mg</em> = <em>ma</em> … … … [2]
<em />
Adding equations [1] and [2] eliminates <em>T</em>, so that
((1 kg) <em>g</em> sin(45°) - <em>T </em>) + (<em>T</em> - (0.4 kg) <em>g</em>) = (1 kg + 0.4 kg) <em>a</em>
(1 kg) <em>g</em> sin(45°) - (0.4 kg) <em>g</em> = (1.4 kg) <em>a</em>
==> <em>a</em> ≈ 2.15 m/s²
The fact that <em>a</em> is positive indicates that the 1-kg block is moving down the slope. We already found the acceleration is <em>a</em> ≈ 2.15 m/s², which means the net force on the block would be ∑ <em>F</em> = <em>ma</em> ≈ (1 kg) (2.15 m/s²) = 2.15 N directed down the slope.
