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mylen [45]
3 years ago
11

How big is earthtoday​

Physics
1 answer:
kaheart [24]3 years ago
7 0

Answer:

3,958.8 mi

Explanation:

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The speed of light in a material is 1.74 x 108 m's. What is the index of refraction of this material?
Ipatiy [6.2K]

Answer:

The index of refraction of this material is 1.7241

Explanation:

Recall that the index of refraction (n) of a medium is defined as the quotient between the speed of light in vacuum divided the speed of light in the medium whose index of refraction is being calculated. In mathematical terms:

n=\frac{c}{v}

Therefore, in our case, since we know the speed of light in the medium (v=1.74\,\,10^8\,\,m/s) and the speed of light in vacuum (c=3\,\,10^8\,\,m/s), we can estimate the index of refraction of the medium:

n=\frac{c}{v} \\n=\frac{3\,\,10^8}{1.74\,\,10^8} \\n=1.7241

3 0
4 years ago
Tony has a mass of 50 kg, and his friend Sam has a mass of 45 kg. Assume that both friends push off on their roller blades with
wolverine [178]
I believe it is D because if the mass is smaller then greater the acceleration for it to be equal force. Hope this helps! Sorry, if I'm wrong. 
3 0
3 years ago
Type AB blood can donate to what blood types ? ( Select all that apply )
abruzzese [7]
The answer will AB
It is able to do all blood types
6 0
3 years ago
Read 2 more answers
A 67.5-kg person throws a 0.0410-kg snowball forward with a ground speed of 34.0 m/s. A second person, with a mass of 57.5 kg, c
lora16 [44]

Answer:

Final velocity of the first person is 3.43m/s and that of the second person is 0.0242m/s

Explanation:

Let the momentum of the first person, the ball second person be Ma, Mb and Mc.

From the principle of the conservation of momentum, sum of the momentum before collision is equal to the sum of the momentum after collision.

Ma1 + Mb1 = Ma2 + Mb2.

The ball and the first person are both moving together with a common velocity 3.45m/s.

Let the velocity of the first person be v1

Therefore

67.5×3.45+ 0.041×3.45= 67.5v1 + 0.041×34

233.02 = 1.39+ 67.5v1

67.5v1 = 233.02 - 1.39 = 231.61

v1 = 231.61 / 67.5

v1 = 3.43m/s

The second person and the ball move together with a common velocity after catching the ball.

For the second person and the ball let their final common velocity be v

Mb2 + Mc2 = Mb3 + Mc3

0.041 × 34 + 57.5 ×0 = (57.5 + 0.041)×v

57.541v = 1.39

v = 1.39 /57.541

v = 0.0242m/s

5 0
4 years ago
If a train travels 500 kilometers from Stockholm to
o-na [289]

Hello,

Average speed is total distance divided by total time. From the problem, our total distance is given as 500 kilometers and given time is 5 hours. Therefore, the average speed is:

\displaystyle{v_\text{average}=\sum_{i=1}^n \dfrac{s_i}{t_i}}\\\\\displaystyle{v=\dfrac{500\ \text{km}}{5 \ \text{h}}}\\\\\displaystyle{v=100 \ \text{km/h}}

Therefore, the average speed is 100 km/h. Please let me know if you have any questions!

4 0
1 year ago
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