Answer:
c
Step-by-step explanation:
count
Answer:
C and D
Step-by-step explanation:
A box plot display consist of a five-number summary. The five-number summary includes the following five values that is depicted in the box plot display:
1. Min value: the least value or smallest value indicated at the end of the whiskers to our left.
2. Max value: the largest value in the data set indicated at the end of the whisker to our right.
3. The median: this is a measure of center indicated by the vertical line that divides the rectangular box into 2.
4. The Upper quartile (Q3): this is indicated by at the end of the rectangular box at our far right.
5. The lower quartile (Q1): this is indicated at the beginning of the rectangular box from our left.
The interquartile range is the difference between the Q3 and the Q1, which can be used as a measure of spread of a data set.
Therefore, the most appropriate measures of center and spread for the data set above, are the median and the interquartile range respectively.
The correct choices are option C and D.
Answer:
The sample size to obtain the desired margin of error is 160.
Step-by-step explanation:
The Margin of Error is given as
Rearranging this equation in terms of n gives
![n=\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2](https://tex.z-dn.net/?f=n%3D%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7BM%7D%5Cright%5D%5E2)
Now the Margin of Error is reduced by 2 so the new M_2 is given as M/2 so the value of n_2 is calculated as
![n_2=\left[z_{crit}\times \dfrac{\sigma}{M_2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{\sigma}{M/2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{2\sigma}{M}\right]^2\\n_2=2^2\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4n](https://tex.z-dn.net/?f=n_2%3D%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7BM_2%7D%5Cright%5D%5E2%5C%5Cn_2%3D%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7BM%2F2%7D%5Cright%5D%5E2%5C%5Cn_2%3D%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B2%5Csigma%7D%7BM%7D%5Cright%5D%5E2%5C%5Cn_2%3D2%5E2%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7BM%7D%5Cright%5D%5E2%5C%5Cn_2%3D4%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7BM%7D%5Cright%5D%5E2%5C%5Cn_2%3D4n)
As n is given as 40 so the new sample size is given as
So the sample size to obtain the desired margin of error is 160.
To find the quotient, we can use a calculator. Problem is that we get a decimal, so 52 won't divide evenly. When using a calculator the whole number part is the quotient.
1052 + 52 = 20.2307692....
Now, 52 x 20 = 1040. Since 1052 - 1040 = 12 we can properly report the quotient and its remainder.
So 1052 + 52 = 20 (its quotient) and 12 (its remainder).
Answer:
2/3
Step-by-step explanation:
There are a total of (3+6) = 9 coins
P( dime) = dimes / total
= 6/9
= 2/3
