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Alexeev081 [22]
3 years ago
14

Jeanette has 3 quarters and 6 dimes in her hand. she accidentally drops one of the coins. what is the probability that the coin

she drops if a dime?
A. 1/2
B. 2/3
C. 2/1
D. 1/9
Mathematics
2 answers:
svetoff [14.1K]3 years ago
6 0

Answer:

Hey there!

Jeanette has 3+6, or 9 coins in total.

6 of the coins are dimes.

Thus, the probability of dropping a dime is 6/9, which can be simplified to 2/3.

Let me know if this helps :)

Nadya [2.5K]3 years ago
4 0

Answer:

2/3

Step-by-step explanation:

There are a total of (3+6) = 9 coins

P( dime) = dimes / total

              = 6/9

              = 2/3

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A.
5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
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B.
3(2x-4)=5x-1 \\
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\boxed{x=11} \Leftarrow \hbox{the second mistake}

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\hbox{add 12 to both sides} \\
x=11
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