How to find x and y I dont understand
2 answers:
Check the picture below.
so... notice "y", is also a vertical angle with the other side.
now, there are a total of 360° total in a circumference... so.... if the left-angle is 68, and the right-angle is also 68, because they're vertical angles, then the remainder is 360 - 68 - 68 which is 224.
now, the remainder has to be split evenly between the two remaing angles, "y" and her twin, thus each one takes half of 224, and thus "y" is half of 224.
so... notice "y", is also a vertical angle with the other side.
now, there are a total of 360° total in a circumference... so.... if the left-angle is 68, and the right-angle is also 68, because they're vertical angles, then the remainder is 360 - 68 - 68 which is 224.
now, the remainder has to be split evenly between the two remaing angles, "y" and her twin, thus each one takes half of 224, and thus "y" is half of 224.
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The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:
Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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