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umka21 [38]
4 years ago
11

Simplify square roots (variables) please show work ;)

Mathematics
1 answer:
7nadin3 [17]4 years ago
5 0

Answer:

3x^{3} \sqrt{6x}

Step-by-step explanation:

\sqrt{57x^{7} }

\sqrt{3^{2}*6x^{2} * x  }

\sqrt{3x^{2} }\sqrt{x^{6} }\sqrt{6x}

3x^{3} \sqrt{6x}

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Answer:

This is an acute triangle

Step-by-step explanation:

Pythagoras theorem is used to determine if a triangle is right, acute or obtuse

If the sum of squares of two shorter lengths is greater than the square of third side then the triangle is an acute triangle.

If the sum of squares of two shorter lengths is less than the square of third side then the triangle is an obtuse triangle.

If the sum of squares of two shorter lengths is equal the square of third side then the triangle is a right triangle.

so,

(40)^2 = (37)^2 + (24)^2\\1600 = 1369+576\\1600

As 1600<1945, the given triangle is an acute triangle ..

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