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umka21 [38]
3 years ago
11

Simplify square roots (variables) please show work ;)

Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0

Answer:

3x^{3} \sqrt{6x}

Step-by-step explanation:

\sqrt{57x^{7} }

\sqrt{3^{2}*6x^{2} * x  }

\sqrt{3x^{2} }\sqrt{x^{6} }\sqrt{6x}

3x^{3} \sqrt{6x}

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Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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Sally divided her 48 spools of thread evenly into six boxes. How many spools of thread did she put into each box?
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Step-by-step explanation:

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