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3 years ago

Simplify square roots (variables) please show work ;)

Mathematics

1 answer:

7nadin3 [17]3 years ago

5 0

Answer:

$3x^{3}$ $\sqrt{6x}$

Step-by-step explanation:

$\sqrt{57x^{7} }$

$\sqrt{3^{2}*6x^{2} * x }$

$\sqrt{3x^{2} }$ $\sqrt{x^{6} }$ $\sqrt{6x}$

$3x^{3}$ $\sqrt{6x}$

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Estimate the quotient for the following problem 645 divided by 69

vampirchik [111]

9.285714285714286 645=650 69=70

6 0

3 years ago

Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.

3 0

3 years ago

the distance from talamunda to velcratianis 700 miles. the rain takes 5 hours to travel the distance. at what unit rate is the t

belka [17]

140 miles per hour to reach your 700 mile goal.

<h2><u><em>Do NOT try this you will crast and die none of us want that to happen to you!</em></u></h2>

5 0

3 years ago

(7/4x-5)+(2y-3.5)+(-1/4x+5)

Mazyrski [523]

Hope this helps you !

6 0

3 years ago

heather has divided $6300 between two invesments, one paying 9%, the other paying 4%. If the return on her investment is $372, h

Ganezh [65]

Assuming that the two investments are X & Y
X + Y = 6300
X = 6300 - Y (1)

9/100X + 4/100 Y = 372 (2)
replacing X from (1) into (2)
9/100(6300-Y) + 4/100 Y = 372
567 - 9/100Y +4/100Y = 372
(-9+4)/100Y = 372 - 567
5/100Y = -195
Y = 100*195/5 = 3900
From (1) we can get X
X = 6300 - 3900 = 2400

I hope this is helpful

6 0

3 years ago