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SpyIntel [72]
4 years ago
8

It's the one about triangle XYZ. ignore my work. I have to find all of the angles.

Mathematics
2 answers:
Lubov Fominskaja [6]4 years ago
8 0
Given all 3 sides you need the Law of Cosines to find the first angle.
Let's say a = 22
b = 21
and c = 29

cos(A) = b^2 + c^2 -a^2 / 2bc
cos(A) = 21*21 + 29*29 -22*22 / 2*21*29
cos(A) = 441 + 841 -484 / 2*21*29
cos(A) = 798 / 1,218
cos(A) = <span> <span> <span> 0.6551724138 </span> </span> </span>
angle A = 49.067 Degrees

For the second angle, we can use the easier Law of Sines.
sin (B) = (b * sin(A)) / a
<span>sin (B) = (21 * sin (49.067)) / 22
</span><span>sin (B) = (21 * 0.75548) / 22
</span>sin (B) = <span> <span> <span> 0.72114 </span> </span> </span>
Angle B = 46.149 Degrees

Angle C is really easy to solve.
Angle C = 180 -49.067 -46.149
Angle C = 84.784


svetlana [45]4 years ago
7 0
X=150
Y=129
Z=137
these are all the angles 
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