Plss help i’ll give brainliest thank you!

If 2(6 + 3x) + 1 = - 5 + 3(x - 1), what is the value of x?

Stels [109]

Answer: x = -7

Step-by-step explanation:

2(6 + 3x) + 1 = - 5 + 3(x - 1)

(2) (6) + (2) (3x) + 1 = -5 + (3) (x) + (3) (-1)

12 + 6x + 1 = - 5 + 3x + - 1

( 6x ) + ( 12 - 1 ) = ( 3x ) + ( -5 + -3 )

6x + 13 = 3x - 8

6x + 13 - 3x = 3x - 8 - 3x

3x + 13 = -8

3x + 13 - 13 = -8 - 13

3x = -21

3x/3 -21/3

X = -7

5 0

3 years ago

Read 2 more answers

It takes julie 75 minutes to read 60 pages.

Viktor [21]

A.
$\frac{15}{12} minutes$
b. 60x=(75x350)pages

c. x= 437.5 minutes
=7 hr 17.5 minutes
=7 hr 18 min (round off)

3 0

3 years ago

I need help ASAP

MrRissso [65]

Answer: 2/9 or 0.22

Step-by-step explanation:

Probability = number of possible outcomes/ number of total outcomes

From the given question, total number of outcomes is 18, which the the sum of all the horses in the stable.

P(brown) = number of brown horses/ total number of horses

= 4/18, simplified to 2/9 as s fraction

= 0.22

I hope this helps.

7 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

liberstina [14]

Answer: C) x = 3, (x = 2 is an extraneous solution)

Step-by-step explanation:

$\frac{x}{x-1}$ - $\frac{1}{x-2}$ = $\frac{2x-5}{x^{2}-3x+2}$

$\frac{x}{x-1}$ - $\frac{1}{x-2}$ = $\frac{2x-5}{(x-1)(x-2)}$

Restrictions: Denominator cannot equal zero (x - 1 ≠ 0) and (x - 2 ≠ 0), so x ≠ 1 and x ≠ 2

$(x - 1)(x - 2)\frac{x}{x-1}$ - $(x - 1)(x - 2)\frac{1}{x-2}$ = $(x - 1)(x - 2)\frac{2x-5}{(x-1)(x-2)}$

x(x - 2) - 1(x - 1) = 2x - 5

x² - 2x - x + 1 = 2x - 5

x² - 3x + 1 = 2x - 5

-2x + 5 -2x + 5

x² - 5x + 6 = 0

(x - 2)(x - 3) = 0

x - 2 = 0 x - 3 = 0

x = 2 x = 3

NOTE: x = 2 is an extraneous solution because it is one of the restricted values.

4 0

3 years ago

Find the value of angle x , angle y, and angle z in figure.

Lynna [10]

$\bf \underline{★ Solution-} \\$

In the given figure, we are given with two lines which are parallel to each other. We are also given with two lines which forms a triangle and also forms as a transversal lines to the parallel lines. We are also given that the given triangle is an isosceles triangle. So, we can say that the other angle in the triangle also measures 75°.

Now, let's find the value of the ∠x.

We know that the alternate angles in the parallel line always measures the same as the one which is in it's alternate side. So,

$\sf \leadsto \angle{x} = {75}^{\circ}$

Now, let's find the value of the ∠z.

We know that, all the angles in a triangle always adds up to 180°. In the given triangle, we are given with two angles, so we can easily find the third angle.

$\sf \leadsto {75}^{\circ} + {75}^{\circ} + \angle{z} = {180}^{\circ}$

$\sf \leadsto {150}^{\circ} + \angle{z} = {180}^{\circ}$

$\sf \leadsto \angle{z} = 180 - 150$

$\sf \leadsto \angle{z} = {30}^{\circ}$

Now, let's find the value of the ∠y.

We know that all the angles that forms a straight line always equals up to 180° (or) the the straight line angle always measures 180°. So, we can find the value of the ∠y by this concept.

$\sf \leadsto {75}^{\circ} + {30}^{\circ} + \angle{y} = {180}^{\circ}$