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Anna71 [15]
3 years ago
5

1 1/3 + 1 2/3 + 1 2/3 + 1 2/3 + 2 + 2 + 2 + 2 1/3 + 3 =

Mathematics
2 answers:
frutty [35]3 years ago
8 0
Try using a calculator next time
The sum is 17 and 2/3
barxatty [35]3 years ago
6 0

Answer:

1 1/3 + 1 2/3 + 1 2/3 + 1 2/3 + 2 + 2 + 2 + 2 1/3 + 3 = 17 \frac{2}{3}

Step-by-step explanation:

To solve this problem, we will follow the steps below;

First lets add all the whole numbers together;

That is; 2 + 2 + 2 + 2 + 3 =11

Then next lets convert all the mixed fraction to improper fraction;

1 1/3 = 4/3      1 2/3 = 5/3

Now lets add up all the fractions together

4/3 + 5/3 + 5/3 +5/3 + 1/3 = 20/3

Now we can now add the value of our whole number and the value of our fraction all together

11 + 20/3   = 33 + 20  /3   =  \frac{53}{3}  =   17 \frac{2}{3}

Therefore

1 1/3 + 1 2/3 + 1 2/3 + 1 2/3 + 2 + 2 + 2 + 2 1/3 + 3 = 17 \frac{2}{3}

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The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation
aliina [53]

Answer:

a.  X~N(2,885, 651)

b.  0.086291

c.  0.00058

d.  3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting  the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

P(X

#substitute the given values in the formula to solve for P:

P(X

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058

Hence, the proportion of customers consuming over  5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0
4 years ago
Let x be a positive integer. If (-3)ºx (-3)* = (-3)14,<br> what is x?
Nezavi [6.7K]

Answer:

-3^{\circ \:}x\left(-3\right)=\left(-3\right)\cdot \:14 : x = \frac{840}{180^{\circ \:}}

Decimal Form:

x = -267.38030...

Step-by-step explanation:

-3^{\circ \:}x\left(-3\right)=\left(-3\right)\cdot \:14

Remove Parentheses: (-a) = -a

-3^{\circ \:}x\left(-3\right)=-3\cdot \:14

Multiply the numbers: 3 * 14  = 42

-3^{\circ \:}x\left(-3\right)=-42

Divide both sides by: -3^{\circ \:}\left(-3\right)

\frac{-3^{\circ \:}x\left(-3\right)}{-3^{\circ \:}\left(-3\right)}=\frac{-42}{-3^{\circ \:}\left(-3\right)}

Simplify:

x=-\frac{840}{180^{\circ \:}}

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

3 0
3 years ago
Perimeter = 26 yards
mel-nik [20]

Answer:

There isn’t a answer

Step-by-step explanation:

Where is the question? I’ll edit the message if there is something that needs to be solved otherwise this doesn’t make sense.

4 0
3 years ago
Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers
Mars2501 [29]

Answer:

a) Let \frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

b)

Let \frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.

Observe that

\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

c)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}

d)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.

Observe that

\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}

3 0
3 years ago
What are the units of a and d​
professor190 [17]

Answer:

61 is the length of AD. Hope this helps!

6 0
3 years ago
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