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Whitepunk [10]
3 years ago
7

Metal mercury at room temperature is a liquid.Its melting point is -39*C.The freezing point of alcohol is -114*C. How much warme

r is the melting point of mercury than the freezing point of alcohol?
Mathematics
2 answers:
vampirchik [111]3 years ago
6 0
-39°C  is  <em>75 Celsius degrees</em> "warmer" than  -114°C . . .
if you could call either one "warm".

( 75 Celsius degrees warmer is the same as 135 Fahrenheit degrees warmer.)
stiv31 [10]3 years ago
4 0
The problem is worded a bit confusing, but think of it as if -39 degrees celcius is the freezing point for mercury. The solution is: 75 degrees Celcius.
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There are 14 thirds in 4 2/3
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belka [17]

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Step-by-step explanation:

6 0
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Rasek [7]

Let's do this by Briot-Ruffini


First: Find the monomial root


x - 2 = 0

x = 2


Second: Allign this root with all the other coeficients from equation

Equation = -3x³ - 2x² - x - 2

Coeficients = -3, -2, -1, -2

2 | -3 -2 -1 -2


Copy the first coeficient


2 | -3 -2 -1 -2

-3


Multiply him by the root and sum with the next coeficient


2.(-3) = -6

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2 | -3 -2 -1 -2

-3 -8


Do the same


2.(-8) = -16

-16 + (-1) = -17


2 | -3 -2 -1 -2

-3 -8 -17


The same,


2.(-17) = -34

-34 + (-2) = -36


2 | -3 -2 -1 -2

-3 -8 -17 -36


Now you just need to put the "x" after all these numbers with one exponent less, see


2 | -3x³ - 2x² - 1x - 2

-3x² - 8x - 17 -36


You may be asking what exponent -36 should be, and I say:


None or the monomial. He's like the rest of this division, so you can say:


(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:

(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)


Just divide the rest by the monomial.

5 0
3 years ago
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yuradex [85]
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6 0
3 years ago
Pls help <br> A.<br> B.<br> C.<br> D.
Alexandra [31]

Answer:

The answer is A so put it

3 0
3 years ago
Read 2 more answers
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