The balloon’s vertical distance above the ground is 570.3 feet
<h3>Angle of elevation and depression</h3>
Given the following parameters
The angle of depression = 36 degrees
Base distance = 785 feet
<h3>Required</h3>
vertical distance above the ground (H)
Using the SOH CAH TOA identity
tan 36 = H/785
H = 785tan36
H = 570.3 feet
Hence the balloon’s vertical distance above the ground is 570.3 feet
Learn more on SOH CAH TOA here: brainly.com/question/20734777
Answer:
The answer is:
58 km/hr
16.1 m/s
Step-by-step explanation:
406 km in 7h
x km in 1h
x= 1 x 406/7
x= 58 km/hr
58 km/hr ⇒⇒⇒⇒⇒⇒ 16.1 m/s
Answer:
Step-by-step explanation:
Step-by-step explanation:
Use the first fundamental theorem of calculus.
∫₆¹⁰ f'(x) dx = f(10) − f(6) = 8 − 8 = 0