How to divide0.8 into 30

Mathematics

2 answers:

Nat2105 [25]3 years ago

8 0

Answer:

pretty easy ヽ(･∀･)ﾉ

Step-by-step explanation:

When you are dividing by a decimal, you have to move the decimal to the right however many places to make it a whole number. In this case if you move the decimal 1 place to the right (that means multiplying by 10) .8 becomes 8. However many places you move the decimal, you have to do the same for the other number. In this case 30.0 becomes 300. Now the problem becomes 300 ÷ 8.

Elden [556K]3 years ago

7 0

The answer would be 37.5!

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Answer:

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Step-by-step explanation:

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A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are

Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

$P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764$