I got 67, is it right? Solve for angle A of the right triangle

Identify the theorem or postulate that is related to the measures of the angles in the pair, and find the unknown angle measures

aleksley [76]

Angles formed when two parallel are intersected by a common transversal include, corresponding, alternate interior and exterior, same-side interior, and vertically opposite angles

The correct option is Same–Side Int. ∠s Thm. m∠1 = 30°, m∠5 = 150°

The reason the selection is correct is as follows:

The given angles are;

m∠1 = (30·x - 30)°. m∠5 = (40·x + 70)°

∠1, and ∠5, are located on the same side of the transversal and are both formed on the interior side of the parallel lines

Therefore, they are same–side interior angles

Same side interior angles theorem states that same side interior angles formed between parallel lines are supplementary

Therefore, we have;

m∠1 + m∠5 = 180°

Which gives;

(30·x - 30)° + (40·x + 70)° = 180°

(70·x + 40)° = 180°

70·x = 180° - 40° = 140°

$x = \dfrac{140^{\circ}}{70} = 2^{\circ}$

m∠1 = (30·x - 30)° = (30 × 2 - 30)° = 30°

m∠1 = 30°

m∠5 = (40·x + 70)° = (40 × 2 + 70)° = 150°

m∠5 = 150°

The correct option is therefore;

Same-Side Int. ∠s Thm. m∠1 = 30°, m∠5 = 150°

Learn more about parallel lines cut by a transversal here:

brainly.com/question/533025

8 0

2 years ago

Need help with AP CAL

anzhelika [568]

Answer: Choice C

$\displaystyle \frac{1}{2}\left(1 - \frac{1}{e^2}\right)$

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Explanation:

The graph is shown below. The base of the 3D solid is the blue region. It spans from x = 0 to x = 1. It's also above the x axis, and below the curve $y = e^{-x}$

Think of the blue region as the floor of this weirdly shaped 3D room.

We're told that the cross sections are perpendicular to the x axis and each cross section is a square. The side length of each square is $e^{-x}$ where 0 < x < 1

Let's compute the area of each general cross section.

$\text{area} = (\text{side})^2\\\\\text{area} = (e^{-x})^2\\\\\text{area} = e^{-2x}\\\\$

We'll be integrating infinitely many of these infinitely thin square slabs to find the volume of the 3D shape. Think of it like stacking concrete blocks together, except the blocks are side by side (instead of on top of each other). Or you can think of it like a row of square books of varying sizes. The books are very very thin.

This is what we want to compute

$\displaystyle \int_{0}^{1}e^{-2x}dx\\\\$

Apply a u-substitution

u = -2x

du/dx = -2

du = -2dx

dx = du/(-2)

dx = -0.5du

Also, don't forget to change the limits of integration

If x = 0, then u = -2x = -2(0) = 0
If x = 1, then u = -2x = -2(1) = -2

This means,

$\displaystyle \int_{0}^{1}e^{-2x}dx = \int_{0}^{-2}e^{u}(-0.5du) = 0.5\int_{-2}^{0}e^{u}du\\\\\\$

I used the rule that $\displaystyle \int_{a}^{b}f(x)dx = -\int_{b}^{a}f(x)dx$ which says swapping the limits of integration will have us swap the sign out front.

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Furthermore,

$\displaystyle 0.5\int_{-2}^{0}e^{u}du = \frac{1}{2}\left[e^u+C\right]_{-2}^{0}\\\\\\= \frac{1}{2}\left[(e^0+C)-(e^{-2}+C)\right]\\\\\\= \frac{1}{2}\left[1 - \frac{1}{e^2}\right]$

In short,

$\displaystyle \int_{0}^{1}e^{-2x}dx = \frac{1}{2}\left[1 - \frac{1}{e^2}\right]$

This points us to choice C as the final answer.

5 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Viktor [21]

Answer:

Step-by-step explanation:

Triangle IJK is a right angle triangle.

From the given right angle triangle

JK represents the hypotenuse of the right angle triangle.

With ∠K as the reference angle,

IK represents the adjacent side of the right angle triangle.

IJ represents the opposite side of the right angle triangle.

To determine Cos K, we would apply trigonometric ratio

Cos θ = adjacent side/hypotenuse. Therefore,

Cos K = 36/85

Cos K = 0.4235

Rounding up to the nearest hundredth,

Cos K = 0.42

4 0

3 years ago

What are two fractions equivalent to 12/14

Andrews [41]

Hey there!

12/14

• BOTH NUMBERS HAVE THE COMMON FACTOR OF 2, SO WE CAN DIVIDE BOTH THE NUMERATOR (TOP number) FROM THE DENOMINATOR (BOTTOM number)

= 12 ÷ 2 / 14 ÷ 2

= 6/7

= 18/21

Therefore, your answer is: 6/7 or 18/21

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0

3 years ago

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F<br> 2. What is the leading coefficient of the polynomial? - 7x2+ 3x -10<br> re

zhenek [66]

Answer:

The leading coefficient is -7

Step-by-step explanation:

The leading coefficient is the number in front of the highest power variable. In this case, the highest variable is x^2 and in front of it is -7. Therefore, the leading coefficient is -7

Answer: The leading coefficient is -7

5 0

3 years ago

Read 2 more answers