Question

Please helpUse numerals instead of words. If necessary, use / for the fraction​

Answer 1

Answer:

1

Step-by-step explanation:

Factor and cancel common factors from numerator and denominator.

$\displaystyle\frac{2y^3-y^2+2y-1}{y^3-y^2+y-1}\times\frac{2y^2-3y+1}{4y^2-4y+1}\\\\=\frac{(y^2+1)(2y-1)\times (2y-1)(y-1))}{(y^2+1)(y-1)\times (2y-1)^2}=\frac{(y^2+1)(2y-1)^2(y-1)}{(y^2+1)(2y-1)^2(y-1)}\\\\=1$