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SashulF [63]
3 years ago
11

Titus works at a hotel. Part of his job is to keep the complimentary pitcher of water at least half full and always with ice. Wh

en he starts his shift, the water level shows 4 gallons, or 128 cups of water. As the shift progresses, he records the level of the water every 10 minutes. After 2 hours, he uses a regression calculator to compute an equation for the decrease in water. His equation is W –0.414t + 129.549, where t is the number of minutes and W is the level of water. According to the equation, after about how many minutes would the water level be less than or equal to 64 cupsss
Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

Answer:

158.33 minutes = 2.63 hours

Step-by-step explanation:

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Sixty-five campers arrive. Nine go home early. If 8 people sleep in 1 tent, how many tents will the campers need?
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4 0
3 years ago
Need help asap please
Dominik [7]
You’re answer is the very last choice, 3.15=315%.
you multiply the decimal by 100 to get 315%.
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4 years ago
How do I solve this using the substitution method for finding anti derivatives?
rewona [7]
A bit blurry, but if I'm making it out correctly, that's

\displaystyle\int t\sqrt{(t^2-9)^3}\,\mathrm dt=\int t(t^2-9)^{3/2}\,\mathrm dt

Set u=t^2-9. Then \mathrm du=2t\,\mathrm dt, or t\,\mathrm dt=\dfrac{\mathrm du}2. The integral is then equivalent to

\displaystyle u^{3/2}\dfrac{\mathrm du}2=\frac12\int u^{3/2}\,\mathrm du
=\dfrac12\dfrac{u^{5/2}}{\frac52}+C
=\dfrac12\times\dfrac25u^{5/2}+C
=\dfrac15u^{5/2}+C
=\dfrac15(t^2-9)^{5/2}+C
6 0
3 years ago
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