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Sever21 [200]
2 years ago
5

15x+3x+19= -17 please help me find this answer

Mathematics
2 answers:
masha68 [24]2 years ago
5 0

Answer:

{ \rm{15x + 3x + 19 =  - 17}} \\  \\ { \rm{18x + 19 =  - 17}} \\  \\ { \rm{18x =  - 17 - 19}} \\  \\ { \rm{18x =  - 36}} \\  \\ { \boxed{ \rm{x =  - 2}}}

NARA [144]2 years ago
4 0

Answer:

<h2><u><em>x = -2</em></u></h2>

Step-by-step explanation:

15x+3x+19= -17 please help me find this answer

15x+3x+19= -17

18x + 19 = -17

18x = -19 - 17

18x = -36

x = -36 : 18

x = -2

---------------

check

15(-2)+3(-2)+19=-17

-30 - 6 + 19 = -17

-17=-17

the answer is good

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2 years ago
Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

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b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

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 ⇒  a² = 5²-3²

          =25 - 9

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The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

7 0
2 years ago
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vfiekz [6]

Answer:

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Compare with (X+a)(X+b)

Where we get a=-8 b=2

8 0
2 years ago
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