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SVETLANKA909090 [29]
3 years ago
15

Aaden wants to get a subscription to an online library. There are two subscription options, one of which charges a fixed 96 doll

ar annual fee and the other which charges 3 dollars per book he borrows.
Mathematics
1 answer:
pishuonlain [190]3 years ago
3 0

Answer:

The data we have is:

Library A charges $96 per year.

Library B charges $3 per book he borrows.

Let's find the number of books X that he needs to borrow in order to spend the same amount in each library:

$3*X = $96

X = 96/3 = 32.

This means that if Aaden borrows 32 books per year, is the same for him if he chooses library A or B.

If he borrows more than 32 books per year, library A will be cheaper. (if he borrows 33 books, library B costs 33*$3 = $99, which is larger than the $96 of library A)

If he borrows less than 32 books per year, library B will be cheaper. (if he borrows 31 books library B costs $3*31 = $93, which is cheaper than the$96 of library A)

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Answer:

(sqrt)x -3=y

Step-by-step explanation:

x=(y+3)^2

\sqrt{x}=\sqrt{(y+3)^{2}

\sqrt{x}=y+3

\sqrt{x}-3=y

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5a +4b+c-3a-c+4b simplified
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2a + 8b

Step-by-step explanation:

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Justine is planting flowers in a line that is 1/2 of a yard long. She is going to plant 6 flowers. How far apart will each flowe
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3 inches apart

Step-by-step explanation:

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1.5 ÷6 = 0.25ft

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6 0
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Arrange the systems of equations in order from least to greatest based on the number of solutions for each system.
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work is shown and pictured

8 0
3 years ago
Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

Read more about the plane

brainly.com/question/1962726

#SPJ4

5 0
1 year ago
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