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anastassius [24]
3 years ago
14

A pharmacist is emptying capsules to create a powder mix for a patient. if a capsule holds 3 . 5 cubic centimeters of medicine,a

bout how many capsules will he need to use to fill a cylinder 2 centimeters in a diameter and 4 centimeters tall?
Mathematics
1 answer:
geniusboy [140]3 years ago
3 0
Volume of cylinder is π(2/2)²(4)=4πcc. Number of capsules=4π/3.5=3.59 capsules, so he will need about 4 capsules to fill the cylinder.
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What is -5.8+(-2.5)
Scilla [17]

-5.8 + (-2.5) = -8.3

since both the number are negative you simply add the numbers and use the negative sign.

5 0
3 years ago
NEED HELP FAST PLEASE.
My name is Ann [436]
I'm pretty sure its A but it could be B
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An airline is planning its staffing needs for the next year. If a new route is​ approved, it will hire 837 new employees. If a n
dusya [7]

Considering a discrete distribution, it is found that the expected number of new employees to be hired by the​ airline is of 446.16.

<h3>What is the mean of a discrete distribution?</h3>

The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.

In this problem, considering the situation described in the text, the distribution is given by:

  • P(X = 837) = 0.37.
  • P(X = 199) = 0.63.

Hence, the expected value is given by:

E(X) = 0.37(867) + 0.63(199) = 446.16.

More can be learned about discrete distributions at brainly.com/question/24855677

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2 years ago
T=35+7p how many pokemon cards does Jackie have in all if the second book has 14 pages?
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5 0
3 years ago
Read 2 more answers
The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
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