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2 years ago

What is the length of segment AB?

Mathematics

1 answer:

olasank [31]2 years ago

7 0

Answer:

The answer is 6.403

Step-by-step explanation:

Using the pythagorean theorem, a^2+b^2=c^2, we can plug 4 units into a, and 5 units into b. Plugging these into the formula results in 4^2 + 5^2 = c^2. Simplifying, we get 16 + 25 = c^2. Simplifying even more, we get 41 = c^2. Using a calculator to get the square root of both sides results in c = 6.40312424.

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The bases of a circular cylinder are two ___ circles.

Blababa [14]

Well,

A cylinder is actually a special type of prism. A prism is a 3-D figure made by taking a simple closed plane curve and translating it across space in a certain direction and for a given distance and then connecting the preimage and the image. A cylinder is just a prism made with a circle.

We know from translations that the image is congruent to the preimage. Thus, the bases of a (circular) cylinder are two congruent circles.

6 0

2 years ago

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Draw a quadrilateral that does not belong, then explain why. What should I draw and write?

Anna007 [38]

Answer

do u have a demonstration

picture

Step-by-step explanation:

6 0

2 years ago

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Please someone help me to prove this.

morpeh [17]

Answer: see proof below

Step-by-step explanation:

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

Proof LHS → RHS

LHS: 2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]

Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]

Distribute: cos²2A + 2cos2A·sin2A + sin²2A

Pythagorean Identity: 1 + 2cos2A·sin2A

Double Angle: 1 + sin4A

LHS = RHS: 1 + sin4A = 1 + sin4A $\checkmark$

6 0

2 years ago

What is the 5% of 300

garik1379 [7]

15
300*5/100 =15
That's all

5 0

2 years ago

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Please help work this out

BigorU [14]

Answer:

Area=190.091 cm^2

Step-by-step explanation:

Area = 1/2(Pi x r^2) one-half because it's a semi-circle

Area=1/2(3.14 x 11^2)

11^2=121 so, Area=1/2(3.14 x 121)

Area=1/2(379.94)

Area=189.97 cm^2

adjustment:

Area=1/2(3.142 x 11^2)

Area=1/2(3.142 x 121)

Area=1/2(380.182)

Area=190.091

5 0

2 years ago