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Usimov [2.4K]
3 years ago
14

Assume each variable has a different value. Which relations below are functions? a. {(a, b), (a, c), (a, d), (a, e)} b. {(a, b),

(b, b), (c, b), (d, b)} c. {(a, b), (c, d), (e, f), (g, h)} d. {(a, a), (b, c), (c, c), (d, e)}
A. choice a only

B. choices b and c only

C. choice c only

D. choices b, c, d only
Mathematics
2 answers:
Inessa05 [86]3 years ago
5 0
I think its D but im not 100% sure let me know if its right
Mashutka [201]3 years ago
3 0

A <u>function</u> is a <u>relation</u> in which every<u> input value</u> x has at most one<u> output value</u> y.

Consider all options:

a. Relation {(a, b), (a, c), (a, d), (a, e)} is not a function, because input value a has four different output values b, c, d and e.

b. Relation {(a, b), (b, b), (c, b), (d, b)} is a function, because every input value a, b, c and d have at most one output value b.

c. Relation {(a, b), (c, d), (e, f), (g, h)} is a function, because every input value a,  c, e and g have at most one output value b, d, f and g, respectively.

d. Relation {(a, a), (b, c), (c, c), (d, e)} is a function, because every input value a,  b, c and d have at most one output value a, c, c and e, respectively.

Answer: correct choice is D

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Let's solve your equation step-by-step.

Question 1:   −2(6−2x) =4(−3+x)

 

Step 1: Simplify both sides of the equation.

−2(6−2x) =4(−3+x)

(−2) (6) +(−2) (−2x) =(4)(−3)+(4)(x)(Distribute)

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Step 2: Subtract 4x from both sides.

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Step 3: Add 12 to both sides.

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Question 2:  

Let's solve your equation step-by-step.

5−1(2x+3) =−2(4+x)

 

Step 1: Simplify both sides of the equation.

5−1(2x+3) =−2(4+x)

5+(−1) (2x) +(−1) (3) =(−2) (4)+(−2)(x)(Distribute)

5+−2x+−3=−8+−2x

(−2x) +(5+−3) =−2x−8(Combine Like Terms)

−2x+2=−2x−8

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Step 2: Add 2x to both sides.

−2x+2+2x=−2x−8+2x

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Step 3: Subtract 2 from both sides.

2−2=−8−2

0=−10

 

Answer: There are no solutions.

 

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