The formula for the Circumference of a circle is 2•Pi•R, or 2•Radius•3.14
This is to calculate the measurements around the circle.
The formula for the Area of a circle is Pi•R^2, or 3.14•R•R
This is to calculate the entire circle.
I hope this helps!
The area of the sector is found by multiplying the area of the circle and the ratio of the angle subtended (measure of the central angle) by the sector to 360.
<h3>How to find the area of a sector?</h3>
1) The formula for area of a sector of a circle is;
A = (θ/360) * πr²
where πr² is area of circle
θ is the angle subtended by the sector
Thus, we conclude that the area of the sector is found by multiplying the area of the circle and the ratio of the angle subtended (measure of the central angle) by the sector to 360.
2) The area of the triangle formed as part of the segment is subtracted from from the area of the sector.
Read more about Area of Sector at; brainly.com/question/22972014
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Step-by-step explanation:
60% of 20 = 12
9514 1404 393
Answer:
(8.49; 225°)
Step-by-step explanation:
The angle is a 3rd-quadrant angle. The reference angle will be ...
arctan(-6/-6) = 45°
In the 3rd quadrant, the angle is 45° +180° = 225°.
The magnitude of the vector to the point is its distance from the origin:
√((-6)² +(-6)²) = √(6²·2) = 6√2 ≈ 8.4859 ≈ 8.49
The polar coordinates can be written as (8.49; 225°).
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<em>Additional comment</em>
My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.
Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.