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3 years ago

={125},={#125}andQ={#125}, finda. ∪ b. ∩ c. d.

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

5 0

Answer:

h3llo

Step-by-step explanation:

hey the answer is in your heart

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How to simplify -6k +7k 12r -8 -12 n -10 +9n -3 -4x-10x -r -10r

Semmy [17]

Answer:

Solve by adding or subtracting like terms. (Ex. 2k + 4k = 6k; 9 + 7 = 16)

- 6k + 7k = 1k = k

(7 - 6 = 1)

12r - 8 - 12 = 12r - 20

(8 + 12 = 20 but sign is negative) 12r will stay the same because there are no terms with a letter r.

n - 10 + 9n - 3 = 9n + n - 10 - 3 = 10n - 10 - 3 = 10n - 13

(n = 1 so 9 + 1 = 10; 10 + 3 = 13 but negative sign)

- 4x - 10x = 14x

(10 + 4 = 14)

- r - 10r = 11r

(r = 1 so 10 + 1 = 11)

6 0

3 years ago

Below an equation is modeled . What value of x makes this equation true?

Strike441 [17]

5x + 6 = 1
Subtract 6 from both sides.
5x = -5
Divide from both sides.
x = -1 (ANSWER)

hope this helps!!

5 0

3 years ago

Prove that sinxtanx=1/cosx - cosx

maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

$\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}$

Taking the RHS, note

$\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}$

Remember that

$\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)$

Therefore,

$\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}$

Once

$\dfrac{\sin(x)}{\cos(x)} = \tan(x)$

Then,

$\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)$

Hence, it is proved

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3 years ago

M=2 and containing the point (7,6)

Law Incorporation [45]

Answer:

$the \: equation \: of \: the \: line \: is \to \\ \boxed{ \underline{y = 2x - 8 }}$

Step-by-step explanation:

$according \: to \: the \: provided \: info : \\ the \: equation \: of \: the \: line \: is \to \\ y - y_{1} = m(x - x_{1}) \\ y - 6 = 2(x -7) \\ y = 2x - 14 + 6 \\ \underline{y = 2x - 8 }$

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3 years ago

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Is the answer C ; y= -3x-1

Sonja [21]

Answer:

I believe you are correct

Hope This Helps! Have A Nice Day!!

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3 years ago

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