Answer:
Explanation:
Given that,
An object starts from rest at the origin (x₀ = 0) and travels in a straight line with a constant acceleration (a = constant).
The relation between the position (x) and time (t) is given by :
Let v is the velocity of the object.
Let a is the acceleration of the object. It is given by :
So, the acceleration of the object is . Hence, this is the required solution.
Answer:
Water is the solvent, therefore (B
Explanation:
Water is called the "universal solvent" because it is capable of dissolving more substances than any other liquid.
This has to do with the polarity of each water molecule. The hydrogen side of each water (H2O) molecule carries a slight positive electric charge, while the oxygen side carries a slight negative electric charge. This helps water dissociate ionic compounds into their positive and negative ions.
Answer:
The work function ϕ of the metal = 53.4196 x 10⁻¹⁶ J
Explanation:
When light is incident on a photoelectric material like metal, photoelectrons are emitted from the surface of the metal. This process is called photoelectric effect.
The relationship between the maximum kinetic energy () of the photoelectrons to the frequency of the absorbed photons (f) and the threshold frequency (f₀) of the photoemissive metal surface is:
= h(f − f₀)
= hf - hf₀
E is the energy of the absorbed photons: E = hf
ϕ is the work function of the surface: ϕ = hf₀
= E - ϕ
Frequency f = 8.12×10¹⁸ Hz
Maximum kinetic energy = 4.16×10⁻¹⁷ J
Speed of light c = 3 x 10⁸ m/s
Planck's constant h = 6.63 × 10⁻³⁴ Js
E = hf = 6.63 × 10⁻³⁴ x 8.12×10¹⁸
E = 53.8356 x 10⁻¹⁶ J
from = E - ϕ ;
ϕ = E -
ϕ = 53.8356 x 10⁻¹⁶ - 4.16×10⁻¹⁷
ϕ = 53.4196 x 10⁻¹⁶ J
The work function of the metal ϕ = 53.4196 x 10⁻¹⁶ J
Answer:
the ratio Kf : Ki is 1 / 4 or 1 : 4
Explanation:
Given the data in the question;
Since this is a perfectly inelastic collision, momentum is conserved;
=
Now for BLOCK 1
mass = M₁ = M
KE = K
mv₁² = K
we solve for v₁
mv₁² = 2K
v₁ = √( 2K / m )
for BLOCK 2
mass = M₂ = 3m and since its at rest v₂ = 0
Now after the collision; Total mass = m + 3m = 4m
KE = K
( 4m )v² = K
(2m)v² = K
v = √(K / 2m)
so since =
[m₁ × v₁] + [m₂ × v₂] = ( m + 3m ) × v
so
[ m₁ × √( 2K / m ) ] + [ m₂ × 0 ] = ( m + 3m ) × [ √(K / 2m) ]
[ m × √( 2K / m ) ] = 4m × [ √(K / 2m) ]
square both side
m² × 2K / m = (4m)² × K / 2m
m² × 2K / m = 16m² × K / 2m
m × 2K = 8m × K
2K = 8K
K = 2K / 8
K / K = 2 / 8
K / K = 1 / 4
Therefore, the ratio Kf : Ki is 1 / 4 or 1 : 4
Answer:
The Buoyant force is
Explanation:
From the question we are told that
The mass of the block is m = 2 kg
Generally the magnitude of the buoyant is equivalent to the weight of the block
Hence the buoyant force is
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