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kolbaska11 [484]
3 years ago
15

Two automobiles are 150 kilometers apart and traveling toward each other. One automobile

Physics
1 answer:
Vladimir79 [104]3 years ago
8 0
Their relative speed is the sum of 60 and 40 or 100km/hr. They will travel the 150km in 1.5 hrs. When two object approach each other, the closing speed is just the sum of the speeds, therefore, the closing speed is your case is 100kph. So they will meet in 1.5 hours.
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A body is acted upon by a force of 4N.
ladessa [460]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Kinematics.

so here we get as,

V^2 = U^2 + 2as

so here, a = -0.2 m/s^2

(0.1)^2 = (0.3)^2 + (-0.2)(s)

=> 0.01 = 0.09 - 0.2s

=> 0.2s = 0.08

=> s = 0.08/0.2

=> s = 0.4 m

7 0
3 years ago
Some superconductors are capable of carrying a very large quantity of current. If the measured current is 1.00 ´ 105 A, how many
Zielflug [23.3K]

Answer:

The 6.25 \times 10^{23} electrons are moving through the superconductor per second.

Explanation:

Given :

Current I = 1 \times 10^{5} A

Charge of electron e = 1.6 \times 10^{-19} C

Time t = 1 sec

From the formula of current,

Current is the number of charges flowing per unit time.

   I = \frac{ne}{t}

Where n = number of charges means in our case number of electrons

   n = \frac{It}{e}

   n = \frac{1 \times 10^{5} }{1.6 \times 10^{-19} }

   n = 6.25 \times 10^{23}

Therefore, 6.25 \times 10^{23} electrons are moving through the superconductor per second.

5 0
3 years ago
Pls quickly brainliest to the first to anwser
fiasKO [112]

Answer:

8m/s^2

Explanation:

hope it helps........

4 0
3 years ago
Read 2 more answers
What force is necessary to keep a mass of 0.8 kg revolving in a horizontal circle of radius 0.7 m with a period of 0.5 s? What i
inn [45]

Answer:

88.34 N directed towards the center of the circle

Explanation:

Applying,

F = mv²/r................... Equation 1

F = Force needed to keep the mass in a circle, m = mass of the mass, v = velocity of the mass, r = radius of the circle.

But,

v = 2πr/t................... Equation 2

Where t = time, π = pie

Substitute equation 2 into equation 1

F = m(2πr/t)²/r

F = 4π²r²m/t²r

F = 4π²rm/t²............. Equation 3

From the question,

Given: m = 0.8 kg, r = 0.7 m, t = 0.5 s

Constant: π = 3.14

Substitute these values into equation 3

F = 4(3.14²)(0.7)(0.8)/0.5²

F = 88.34 N directed towards the center of the circle

8 0
3 years ago
Oxygen has an atomic number of 8. What can you conclude from this fact?
Alja [10]

Answer:

The answer to your question is below

Explanation:

If Oxygen has an atomic number of 8, we can conclude that:

- If neutral, it has 8 protons and 8 electrons

- It has 8 neutrons and its atomic mass is 16 (A = 8 + 8)

- It must be located in the group VI A

- Its valence number must be 6

- Its Oxidation number is -2

7 0
3 years ago
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