Answer:
8o F at least I'm pretty sure 101o F ≥ 8o
Step-by-step explanation:
Correct me If im wrong
The Answer to the problem is X=3 because sice it is equidistant you do 2x+24 = 30 and subtract 24 from 30 then you will get 2x=6 tben you divide 2 frkm both sides and you will have x=3
We know that
A line tangent to a circle is perpendicular to the radius to the point of tangency.
so
<span>Line ef is </span>perpendicular to the segment gh
hence
Triangle FHG is a right triangle
The first equation is separable:
dy/dx = x/y ⇒ y dy = x dx
(provided that y ≠ 0)
Integrating both sides yields
1/2 y² = 1/2 x² + C
Given that y(0) = -8, we find
1/2 • (-8)² = 1/2 • 0² + C ⇒ C = 32
so that the particular solution is
1/2 y² = 1/2 x² + 32
Solving for y explicitly, we have
y² = x² + 64
y = ± √(x² + 64)
but since y(0) is negative, we take the negative solution:
y = - √(x² + 64)
The second equation is also separable:
du/dt = (2t + sec²(t)) / (2u) ⇒ 2u du = (2t + sec²(t)) dt
Integrate both sides:
u² = t² + tan(t) + C
Given u(0) = -6, we have
(-6)² = 0² + tan(0) + C ⇒ C = 36
and so
u² = t² + tan(t) + 36
u = ± √(t² + tan(t) + 36)
but again we take the negative root here to agree with the initial condition, so
u = - √(t² + tan(t) + 36)
This is the concept of trigonometry;
Using the Pythagorean theorem, the elevation of the starting point will be given by:
c^2=a^2+b^2
c^2=7^2-3^2
c^2=49-9
c^2=40
thus;
c=6.325 km
therefore the starting point of the camp was:
6.325-0.6
=5.725 km
The answer is 5.725
