Hello,
any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|
<span>In this problem, to find the answer we have to setup a series of ratios that relate the scale to real life distance. We know that 1cm = 2.50km, so that ratio would be 1cm/2.5km. For two towns that are 4.75cm apart on the map, we set a ration of 4.75cm/x km, where x is the actual distance. Now we set the ratios equal to each other and solve for x. 1/2.5=4.75/x where x = 4.75*2.5/1 = 11.875 and rounding up we get 11.88 km. The two towns are actually 11.88 km apart from each other.</span>
Divide 224 by 8 and you will get 28.
Surface area of a sphere=4pi(r^2)
Volume of a sphere=(4/3)pi(r^3)
You need to find the r value to calculate surface area, so I'll solve for that first.
(4/3)pi(r^3)=2254pi
(4/3)(r^3)=2254
r^3=1690.5
r=(1690.5)^(1/3), around 11.9126m
Substitute this in to find surface area
A=4pi(r^2)=4pi(11.9126)^2
=1783.2818 m^2
Hello,
I suppose equations are:
x+y=3 (1)
x+2y=9 (2)
(2)-(1)==>y=6
(1)==>x=3-6
x=-3, y=6
Sol={(-3,6)}
