Use the laws of Boolean algebra to show that the two Boolean expressions in each pair are equivalent. Show that a. xy + xy = x.
b.Show that xy + zx = (x + y)(z + x) c. x + xy = x
1 answer:
Answer:
a) b) and c) is proven :)
Step-by-step explanation:
a)
( For a) we used Boolean law
like always true, and
a1=1a= a)
b)
( For we used double negation
, and De Morgans law
and
)
c) x+xy=x(1+y)=x1=x
(For c) we used Distribution law a(b+c)=ab+ac, and identity a1=1a=a)
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