Question

WILL GIVE 99 POINTS IF ANSWERED ASAP PLEASE

Answer 1

Part A

1) Perimeter of the outside edges

24 inches

2) One possibility is:

length- 8 inches

and width - 8 inches

3) Area of the wood portion

= 11

4) New dimensions are:

Length - 17.5 feet

Width - 12.5 feet

Part B

Area of the picture

- 24

Area of the frame

- 35

Step-by-step explanation:

first part-

1) Perimeter of the outside edges = 2(length + width)

= 2(7 + 5)

= 2(12)

= 24 in

2) if the area of the frame was 64 then there are two possible dimensions

8 × 8 and 16 × 4

the first possibility

length = 8 inches

width = 8 inches

the second possibility

length = 16 inches

width = 4 inches

3) Area of the wood portion= Area of frame - Area of picture

= (5 × 7) - (4 × 6)

= 35 - 24

= 11

4)The scale factor

1 inches = 2.5 feet

length = 7 inches

= 7(2.5)

= 17.5 feet

width = 5 inches

= 5(2.5)

= 12.5 feet

Second part-

Length of picture

= 6 inches

Width of picture

= 4 inches

Area of the picture

(Length × Width)

= 6 × 4

= 24

Length of frame = 7 inches

Width of frame = 5 inches

Area of frame = 7 × 5 = 35

If this helped you please say thanks and mark brainliest

Answer 2

Answer:

Part A

1.  Perimeter of the outside edges = 24 inches

2.  One possibility is: length = 8 in. and width = 8 in.

second possibility is: length = 16 in. and width = 4 in.

3.  Area of the wood portion = 11 $inches^{2}$

4.  New dimensions are:

Length = 17.5 ft.

Width = 12.5 ft.

Part B

Area of the picture = 24 $inches^{2}$

Area of the frame = 35 $inches^{2}$

Step-by-step explanation:

Part A

1.  Perimeter of the outside edges = 2(length + width)

= 2(7 + 5)

= 2(12)

= 24 inches

2.  If the area of the frame was 64 $inches^{2}$, then the two possible dimensions are:

8 × 8 and 16 × 4

i.e., one possibility is: length = 8 in. and width = 8 in.

second possibility is: length = 16 in. and width = 4 in.

3.  Area of the wood portion = Area of the frame - Area of the picture

= (5 × 7) - (4 × 6)

= 35 - 24

= 11 $inches^{2}$

4.  The scale factor is:

1 in. = 2.5 ft.

So, its length = 7 in. = 7(2.5) = 17.5 ft.

width = 5in. = 5(2.5) = 12.5 ft.

Part B:

Length of the picture = 6in.

Width of the picture = 4 in.

Area of the picture = Length × Width

= 6 × 4

= 24 $inches^{2}$

Length of the frame = 7in.

Width of the frame = 5 in.

Area of the frame = 7 × 5 = 35 $inches^{2}$