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galina1969 [7]
3 years ago
15

What is the value of the discriminant for the quadratic equation 0=2x^2+x-3

Mathematics
1 answer:
xenn [34]3 years ago
4 0
You use the equation Ax^2 + Bx + C to solve this equation.

The answer is 25.

I hope this helps :D
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How to write 9 thousands 3 hundreds 4 ones
Nataly [62]

the answer is 9304=9 thousands 3 hundreds 4 ones

5 0
3 years ago
Read 2 more answers
A rectangular prism has a length of 9 centimeters, a width of 4 centimeters, and a height of 2 centimeters.
RUDIKE [14]

Answer:

It will be 72cm

Step-by-step explanation:

Volume of a rectangular prism = (length x width x height) cubic units.

9x4x2=72

5 0
3 years ago
Find the particular solution that satisfies the differential equation and the initial condition.
Vesnalui [34]

Answer:

1) y =4x^2 +7

2) y =7s^2 -3s^4 +181

Step-by-step explanation:

Assuming that our function is y = f(x) for the first case and y=f(s) for the second case.

Part 1

We can rewrite the expression like this:

\frac{dy}{dx} =8x

And we can reorder the terms like this:

dy = 8 x dx

Now if we apply integral in both sides we got:

\int dy = 8 \int x dx

And after do the integrals we got:

y = 4x^2 +c

Now we can use the initial condition y(0) =7

7 = 4(0)^2 +c, c=7

And the final solution would be:

y =4x^2 +7

Part 2

We can rewrite the expression like this:

\frac{dy}{ds} =14s -12s^3

And we can reorder the terms like this:

dy = 14s -12s^3 dx

Now if we apply integral in both sides we got:

\int dy = \int 14s -12s^3 ds

And after do the integrals we got:

y = 7s^2 -3s^4 +c

Now we can use the initial condition y(3) =1

1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181

And the final solution would be:

y =7s^2 -3s^4 +181

7 0
3 years ago
Find angle, a.  Show the working mentioning the angle properties in each step.​
svetoff [14.1K]

Answer:

a°=45°

Step-by-step explanation:

SOLUTION,

→a°=45°[ Being alternate angles]

→Hence,a°=45°

5 0
2 years ago
Perform the indicated operations,
Natalija [7]

Answer:

{1,3,4,5,6,7}

Step-by-step explanation:

Here , U represents the universal set

L’ = {2,4,6}

L’ is what we have in the universal set but not present in set L

(m n L’)

This is the set that contains the elements that are present in both set ONLY

So this is;

{2}

(M n L’)’ = {1,3,4,5,6,7}

N’ = {1,7}

So the union of both would be;

= {1,3,4,5,6,7}

3 0
2 years ago
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