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3 years ago

Can you help me please?

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

5 0

Answer:

The answer is no,because different inputs (number of pounds of bananas) will have different output(costs)

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George has $49 which he decides to spend on x and y. commodity x costs $5 per unit and commodity y costs $11 per unit. he has th

FromTheMoon [43]

We are given the equations:

5 x + 11 y = 49 --> eqtn 1

u = 3 x^2 + 6 y^2 --> eqtn 2

Rewrite eqtn 1 explicit to y:

11 y = 49 – 5 x

y = (49 – 5x) / 11 --> eqtn 3

Substitute eqtn 3 to eqtn 2:

u = 3 x^2 + 6 [(49 – 5x) / 11]^2

u = 3 x^2 + 6 [(2401 – 490 x + 25 x^2) / 121]

u = 3 x^2 + 14406/121 – 2940x/121 + 150x^2/121

u = 4.24 x^2 – 24.3 x + 119.06

Derive then set du/dx = 0 to get the maxima:

du/dx = 8.48 x – 24.3 = 0

solving for x:

8.48 x = 24.3

x = 2.87

so y is:

y = (49 – 5x) / 11 = (49 – 5*2.87) / 11

y = 3.15

Answer:

George will choose some of each commodity but more y than x.

7 0

3 years ago

A shirt is regularly priced at 42$. It is on sale for 15% off of the regular price. What is the sale price of the shirt ?

gulaghasi [49]

Answer:

$35.7

Step-by-step explanation:

you can convert 15% to a decimal by dividing by 100.

15/100 = .15

if you multiply the decimal by the cost of the shirt you get how much the discount is.

0.15 * $42 = 6.30

so a 15% discount on a $42 shirt is $6.30 off. So you subtract the discount from the total cost.

$42 - $6.30 = $35.70 that is the sale price of the shirt.

4 0

2 years ago

Read 2 more answers

Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )

Zina [86]

Answer:

$\purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ \sqrt{6} }{6} = \frac{1}{ \sqrt{6} } \\ \\ \therefore \: \sin( \alpha ) = \sqrt{1 - { \cos}^{2} ( \alpha ) } \\ \\ = \sqrt{1 - \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} } \\ \\ = \sqrt{1 - {\frac{1}{ {6} }}} \\ \\ = \sqrt{ {\frac{6 - 1}{ {6} }}} \\ \\ \red{\sin( \alpha ) = \sqrt{ { \frac{5}{ {6} }}} } \\ \\ \tan( \alpha ) = \frac{\sin( \alpha ) }{\cos( \alpha ) } = \sqrt{5} \\ \\ \sin( \beta ) = \frac{ \sqrt{2} }{4} \\ \\ \implies \: \cos( \beta ) = \sqrt{ \frac{7}{8} } \\ \\ \tan( \beta ) = \frac{\sin( \beta ) }{\cos( \beta ) } = \frac{1}{ \sqrt{7} } \\ \\ \tan( \alpha - \beta ) = \frac{ \tan \alpha - \tan \beta }{1 + \tan \alpha . \tan \beta} \\ \\ = \frac{ \sqrt{5} - \frac{1}{ \sqrt{7} } }{1 + \sqrt{5} . \frac{1}{ \sqrt{7} } } \\ \\ = \frac{ \sqrt{35} - 1 }{ \sqrt{7} + \sqrt{5} } \\ \\ \purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$